Question

我有一个使用NLTK查找名词和动词的代码。

from nltk.corpus import wordnet as wn
from nltk import pos_tag
import nltk


sentence = "Hello my name is Abhishek Mitra"
sentence = nltk.word_tokenize(sentence)
sent = pos_tag(sentence)
print sent

它返回：

[('Hello', 'NNP'), ('my', 'PRP$'), ('name', 'NN'), ('is', 'VBZ'), ('Abhishek', 'NNP'), ('Mitra', 'NNP')]

如何从列表中仅删除“NN”字样。

Answer 1

您可以使用列表推导来删除'NN'元素：

from nltk.corpus import wordnet as wn
from nltk import pos_tag
import nltk

sentence = "Hello my name is Abhishek Mitra"
sentence = nltk.word_tokenize(sentence)
sent = pos_tag(sentence)
print [s for s in sent if s[1] != 'NN']

Answer 2

a = [('Hello', 'NNP'), ('my', 'PRP$'), ('name', 'NN'), ('is', 'VBZ'), ('Abhishek', 'NNP'), ('Mitra', 'NNP')]

c = [b  for b in a if b[-1] != 'NN']

Answer 3

我会使用过滤功能：

>>> filter(lambda (word, tag): tag != 'NN', sent)
[('Hello', 'NNP'), ('my', 'PRP$'), ('is', 'VBZ'), ('Abhishek', 'NNP'), ('Mitra', 'NNP')]

Answer 4

还有另一种方法（利用元组的优势）：

<div class="father">
  <div class="son">
  </div>
</div>

.father{
  position:relative;
  width:300px;
  height:300px;
  border:1px solid red;
}

.son{
  position:absolute;
  width:100px;
  height:100px;
  border:1px solid red;

}

.son:hover {
    -webkit-transition: all 0.5s ease;
    -webkit-animation: fadein_1 0.2s ease-in;
}

@-webkit-keyframes fadein_1 {
    from { opacity: 1;left:auto;z-index:2;  }
    to { opacity: 0; left:10px;z-index:3; }
}

输出：

from nltk.corpus import wordnet as wn
from nltk import pos_tag
import nltk

sentence = "Hello my name is Abhishek Mitra"
sentence = nltk.word_tokenize(sentence)
sent = pos_tag(sentence) 
sent_clean = [x for (x,y) in sent if y not in ('NN')]

print(sent_clean)

说明： 在代码中：

['Hello', 'my', 'is', 'Abhishek', 'Mitra']

在POS标记句子中的每个单词之后，您将尝试为由于POS标记而创建的元组提取单词。您指定要提取的条件是第二部分

类似地，如果您要消除多个POS：

sent_clean = [x for (x,y) in sent if y not in ('NN')]

输出：

sent_clean2 = [x for (x,y) in sent if y not in ('PRP$', 'VBZ', 'NN')]

print(sent_clean2)

从NTLK pos_tag中仅删除'NN'字样'

4 个答案: