我正在制作一个Android应用程序,其中我使用两个微调器。在第一个微调器中,我正在显示来自JSON的数据,我已经成功完成了。现在,通过单击第一个微调器的项目,我需要将来自另一个JSON服务的数据显示到第二个微调器。
第一次服务(我在第一个微调器上显示此服务的city_name
):
{"result":{"data":[{"city_id":"16","city_name":"\u00c4ngelholm"},
{"city_id":"23","city_name":"B\u00e5stad"},
{"city_id":"22","city_name":"Halmstad"},
{"city_id":"19","city_name":"H\u00f6gan\u00e4s"},{"city_id":"20","city_name":"Helsingborg"},
{"city_id":"15","city_name":"Klippan"},
{"city_id":"24","city_name":"Kungsbacka"},
{"city_id":"21","city_name":"Laholm"},{"city_id":"18","city_name":"Landskrona"}],
"status":"true","description":""}}
第二次服务:
{"result":{"data":[{"category_id":"18","category":"Aff\u00e4rsverksamhet",
"city_id":"16","city_name":"\u00c4ngelholm"},{"category_id":"19","category":"\u00d6vrigt",
"city_id":"16","city_name":"\u00c4ngelholm"},{"category_id":"13","category":"Bostad",
"city_id":"16","city_name":"\u00c4ngelholm"},{"category_id":"15","category":"Elektronik",
"city_id":"16","city_name":"\u00c4ngelholm"},{"category_id":"12","category":"F\u00f6r hemmet","city_id":"16","city_name":"\u00c4ngelholm"},{"category_id":"11","category":"Fordon",
"city_id":"16","city_name":"\u00c4ngelholm"},
{"category_id":"16","category":"Fritid & Hobby",
"city_id":"16","city_name":"\u00c4ngelholm"}],
"status":"true","description":""}}
正如您在服务city_id
和city_name
中看到的那样,是常见字段。如果我从第一个微调器中选择city_name
,它将通过city_id
或city_name
匹配,并针对该category
显示city_name
。
以下是我尝试的代码。
private class AllCities extends AsyncTask<String, String, JSONObject>
{
@Override
protected void onPreExecute()
{
super.onPreExecute();
}
@Override
protected JSONObject doInBackground(String... params)
{
try
{
HttpClient client = new DefaultHttpClient();
HttpPost post = new HttpPost("url of First Service");
HttpResponse resp = client.execute(post);
HttpEntity entity = resp.getEntity();
String response = EntityUtils.toString(entity);
return new JSONObject(response);
}
catch(Exception ex)
{
ex.printStackTrace();
}
return null;
}
@Override
protected void onPostExecute(JSONObject result)
{
super.onPostExecute(result);
if(result != null)
{
myList = new ArrayList<HashMap<String,String>>();
if(! result.has("false"))
{
try
{
JSONObject object = result.getJSONObject("result");
JSONArray array = object.getJSONArray("data");
stringArray = new ArrayList<String>();
for(int i=0; i<array.length(); i++)
{
HashMap<String, String> map = new HashMap<String, String>();
map.put("city_id", array.getJSONObject(i).getString("city_id"));
map.put("city_name", array.getJSONObject(i).getString("city_name"));
myList.add(map);
stringArray.add(array.getJSONObject(i).getString("city_name"));
}
ArrayAdapter<String> adapter = new ArrayAdapter<String>(PostAdds.this,
android.R.layout.simple_spinner_item, stringArray);
adapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
spinner_city.setAdapter(adapter);
}
catch(Exception ex)
{
ex.printStackTrace();
}
}
}
else if(result == null)
{
Toast.makeText(PostAdds.this,
"Hittade inga Detaljer Vänligen Kontrollera din Internet-anslutning",
Toast.LENGTH_LONG).show();
}
}
}
@Override
public void onItemSelected(AdapterView<?> parent, View view, int position, long id)
{
//what am I suppose to do here????
}
@Override
public void onNothingSelected(AdapterView<?> parent)
{
}
答案 0 :(得分:0)
对于迟到的答案感到抱歉。我自己解决了这个问题,但从未回到这里发布适用于我的解决方案。现在我发布这个答案,如果有任何人遇到同样的问题可以从这里得到帮助。
所以我做了什么
1)调用第一个服务并在第一个微调器上填充城市名称,当选择第一个微调器的项目时,将其值保存在全局字符串中,如
String selectedCity;
selectedCity = spinner1.getSelectedItem().toString();
2)当点击第一个微调器的任何项目时,调用第二个服务并在填充第二个微调器时进行简单检查。
ArrayList<String> categories = new ArrayList<String>();
try {
JSONObject object = result.getJSONObject("result");
JSONArray array = object.getJSONArray("data");
for(int a = 0; a < array.length(); a++) {
String cityName = array.getJSONObject(a).getString("city_name");
if(cityName.equals(selectedCity)) // this check is important
{
categories.add(cityName );
}
}
// after for loop ends populate adapter of second spinner
ArrayAdapter<String> adapt = new ArrayAdapter<String>(context, android.R.layout.simple_list_item_1, categories);
spinner2.setAdapter(adapt);
}
catch(Exception e) {
e.printStackTrace();
}
通过这种方式,我获得了理想的结果。还有其他解决方案,这个问题就像其中一个就是当你调用第二个服务时传递city_id或city_name以及url作为params,service只会返回你想要的类别。
希望这会解决任何一个有类似问题的人。我今天只检查了我的Stackoverflow
个人资料,发现这个问题没有得到任何人的回答,所以我自己做了:)