Question

这是我的任务：

编写一个程序，从键盘读取文本，直到'！'找到了。

使用由'A'到'Z'字母下标的整数数组，   计算每个字母的出现次数（无论是否   是大写或小写）。在一个单独的柜台，也计算总数   “其他”字符的数量。

打印出找到的每个字母的计数。另外，打印非字母的计数   字符。

通过检查阵列，打印出元音数量的计数，   和辅音的数量。

这是我的代码：

msg = input("What is your message? ")

print ()

num_alpha = 26
int_array = [0] * num_alpha
vowel = [0] * 10000
consanant = [0] * 10000

for alpha in range(num_alpha):
    int_array[alpha] = chr(alpha + 65)
    if int_array[alpha] == 'A' or int_array[alpha] == 'E' or int_array[alpha] == 'I' or int_array[alpha] == 'O' or int_array[alpha] == 'U':
        vowel[alpha] = int_array[alpha]
        print(vowel[alpha])
    else:
        consanant[alpha] = int_array[alpha]



print()

lett = 0
otherch = 0
num_vowels = 0
num_consanants = 0

count_character = [0] * 100000

length = len(msg)

for character in msg.upper():
    if character == "!":
        otherch = otherch + 1
        count_character[ord(character)] = count_character[ord(character)] + 1
        break
    elif character < "A" or character > "Z":
        otherch = otherch + 1
        count_character[ord(character)] = count_character[ord(character)] + 1
    else:
        lett = lett + 1
        count_character[ord(character)] = count_character[ord(character)] + 1
        if vowel[(alpha)] == (character):
            num_vowels = num_vowels + 1
            print(vowel[alpha])
        else:
            num_consanants = num_consanants + 1

print("Number of Letters =", lett)
print("Number of Other Characters = ", otherch)
print("Number of Vowels = ", num_vowels)
print("Number of Consanants = ", num_consanants)


for character in msg.upper():
        print("Character", character, "appeared" , count_character[ord(character)] , "time(s).")
        if character == "!":
            break

每次输入字符串时都不会识别元音。如果我要输入“abe！”它会打印出来：

Number of Letters = 3 
Number of Other Characters =  1 
Number of Vowels=  0 
Number of Consanants =  3 
Character A appeared 1 time(s). 
Character B appeared 1 time(s). 
Character E appeared 1 time(s).
Character ! appeared 1 time(s).

Answer 1

if vowel[(alpha)] == (character):
  num_vowels = num_vowels + 1
  print(vowel[alpha])

在此代码中，您的alpha超出了范围，这意味着alpha将是前一个for循环的最后一次迭代中的任何内容

我还建议使用in

更好地检查元音

vowels = ['a','e','i','o','u']
char = 'a'
if char in vowels:
  pass              # you have found a vowel

Answer 2

您需要在此处指定alpha。否则，它会将for循环的最后一个值置于顶部（因此它将为25）。

else:
    lett = lett + 1
    count_character[ord(character)] = count_character[ord(character)] + 1
    alpha = ord(character) - ord('A') # <-- need this
    if vowel[(alpha)] == (character):
        num_vowels = num_vowels + 1
        print(vowel[alpha])
    else:
        num_consanants = num_consanants + 1

如何使用数组计算输入中的元音和辅音？

2 个答案: