phpMailer - 发送电子邮件然后给出500错误

Question

我今天一直在努力（几天前刚刚开始学习PHP）。我一直在尝试从php文件，gmail等发送一个表单。这很好用。但是，在完成所有操作后，它仍然会出错。
所以电子邮件发送，但它使用户感到困惑，它使它看起来没有。

我是用tutorial做的。解释所有这一切的家伙真的投入了大量的JavaScript和CSS。我试图避免大部分内容。现在，在邮件发送后我留下了很多代码，我不明白，它打破了我的联系页面，因为一切都很好，然后当它试图完成脚本服务器出错时。

有没有办法让任何人都可以查看我当前的设置，看看在发送邮件后可以做些什么来使php文件与HTML一致？

的 HTML：

<form method="post" action="contact_form.php">
             <p>
                <label for="name">Name:</label>
                <input name="name" type="text" class="txt" id="name" size="30" />
            </p>
             <p>
                <label for="company">Company:</label>
                <input name="company" type="text" class="txt" id="company" size="30" />
             </p>
              <p>
                <label for="city">Email:</label>
                <input type="text" name="email" id="email" class="txt" />
              </p>
             <p>
                <label for="comments">Comments:</label>
                <textarea name="comments" cols="30" rows="5" class="txtarea" id="comments"></textarea>
             </p>
             <p>
                <label for="blank">&nbsp;</label>
                <input type="submit" name="btn_submit" id="btn_submit" class="btn" value="Send"/>
             </p>
    </form>

的 Contact_form.php：

<?php

$name = trim($_POST['name']);
$company = $_POST['company'];
$email = $_POST['email'];
$comments = $_POST['comments'];

$site_owners_email = 'support@macnx.com'; // Replace this with your own email address
$site_owners_name = 'Landin'; // replace with your name

if (strlen($name) < 2) {
    $error['name'] = "Please enter your name";  
}

if (!preg_match('/^[a-z0-9&\'\.\-_\+]+@[a-z0-9\-]+\.([a-z0-9\-]+\.)*+[a-z]{2}/is', $email)) {
    $error['email'] = "Please enter a valid email address"; 
}

if (strlen($comments) < 3) {
    $error['comments'] = "Please leave a comment.";
}

if (!$error) {

    require_once('phpMailer/class.phpmailer.php');
    $mail = new PHPMailer();

    $mail->From = $email;
    $mail->FromName = $name;
    $mail->Subject = "Website Contact Form";
    $mail->AddAddress($site_owners_email, $site_owners_name);
    $mail->Body = $email . $company . $comments;

    // GMAIL STUFF

    $mail->Mailer = "smtp";
    $mail->Host = "smtp.gmail.com";
    $mail->Port = 587;
    $mail->SMTPSecure = "tls"; 

    $mail->SMTPAuth = true; // turn on SMTP authentication
    $mail->Username = "inquiry@getgearhead.com"; // SMTP username
    $mail->Password = "B******A"; // SMTP password

    $mail->Send();

    echo "<li class='success'> Congratulations, " . $name . ". We've received your email. We'll be in touch as soon as we possibly can! </li>";

} # end if no error
else {

    $response = (isset($error['name'])) ? "<li>" . $error['name'] . "</li> \n" : "";
    $response .= (isset($error['email'])) ? "<li>" . $error['email'] . "</li> \n" : "";
    $response .= (isset($error['comments'])) ? "<li>" . $error['comments'] . "</li>" : "";

    echo $response;
} # end if there was an error sending?>

这是$ mail-＆gt; Send（）之后的所有代码;那给了我麻烦。一切都发送花花公子，但然后错误。任何人都知道一种方法，我可以修改php和html文件的代码，以获得发送表单的人的成功消息，而不是服务器500错误。

谢谢！