Question

您试图从db表中获取记录根据比赛的最高比例

 user_id| game         | CompletePercentage
----------------------------------
 1      | name1        | 90
 2      | name2        | 67
 3      | name4        | 100
 4      | name1        | 50
 1      | name4        | 80
 1      | name3        | 70
 1      | name1        | 60
 2      | name2        | 70
 1      | name1        | 50

因此，如果我想获取所有已播放游戏的user_id 1记录，但只有最高

user_id | game         | highestPercent
----------------------------------
 1      | name1        | 90
 1      | name4        | 80
 1      | name3        | 70

我一直在尝试

SELECT user_id, game , MAX(CompletePercentage) AS highestPercent 
FROM completedscenarios 
GROUP BY game 
HAVING user_id=1

但成效有限任何帮助表示赞赏。

Answer 1

SELECT user_id, game, CompletePercentage as highestPercentage
FROM completedscenarios 
WHERE user_id = 1 
ORDER BY CompletePercentage DESC
LIMIT 3

按百分比排序，MAX仅给出一个最大值。由于您希望按所需列添加多个记录顺序，并使用LIMIT修剪该集。

Answer 2

您可以尝试像fiddle这样的自我加入：

为了扩展您可以使用它的其他一些方法，我已将原始小提琴更新为this。此外，我为用户4添加了一个额外的数据点，以显示重复项的内容。

获取一个用户的数据（原始查询）：

SELECT c1.*
FROM completedscenarios c1
  LEFT JOIN completedscenarios c2 
    ON c1.user_id = c2.user_id 
      AND c1.game = c2.game 
      AND c1.CompletePercentage < c2.completePercentage
WHERE c1.user_id = 1 and c2.user_id is null;

获取所有用户及其每场比赛的最佳得分

SELECT c1.user_id, c1.game, c1.CompletePercentage
FROM completedscenarios c1
  LEFT JOIN completedscenarios c2 ON c1.user_id = c2.user_id 
    AND c1.game = c2.game 
    AND c1.CompletePercentage < c2.completePercentage
WHERE c2.user_id is null
ORDER BY c1.user_id, c1.CompletePercentage;

无论用户是什么，都能获得所有游戏和最高百分比

SELECT c1.game, c1.user_id, c1.CompletePercentage
FROM completedscenarios c1
  LEFT JOIN completedscenarios c2 ON c1.game = c2.game 
    AND c1.CompletePercentage < c2.completePercentage
WHERE c2.game is null
ORDER BY c1.game, c1.CompletePercentage;

获得用户及其最佳整体游戏

SELECT c1.user_id, c1.game, c1.CompletePercentage
FROM completedscenarios c1
  LEFT JOIN completedscenarios c2 ON c1.user_id = c2.user_id 
    AND c1.CompletePercentage < c2.completePercentage
WHERE c2.user_id is null
ORDER BY c1.user_id, c1.CompletePercentage;

这是结果的副本

USER_ID | GAME  | COMPLETEPERCENTAGE
------------------------------------
1       | name1 | 90
1       | name4 | 80
1       | name3 | 70

USER_ID | GAME  | COMPLETEPERCENTAGE
------------------------------------
1       | name3 | 70
1       | name4 | 80
1       | name1 | 90
2       | name2 | 70
3       | name4 | 100
4       | name1 | 50
4       | name2 | 70

GAME  | USER_ID | COMPLETEPERCENTAGE
------------------------------------
name1 | 1       | 90
name2 | 2       | 70
name2 | 4       | 70
name3 | 1       | 70
name4 | 3       | 100

USER_ID | GAME  | COMPLETEPERCENTAGE
------------------------------------
1       | name1 | 90
2       | name2 | 70
3       | name4 | 100
4       | name2 | 70

Answer 3

SELECT  user_id,
        game,
        MAX(CompletePercentage) AS highestPercent
  FROM completedscenarios
  GROUP BY user_id, game
  WHERE user_id=1

Answer 4

 SELECT user_id, game,CompletePercentage as highestPercent 
 FROM completedscenarios 
 WHERE user_id=1 
 ORDER BY highestPercent DESC
 Limit 5`

Answer 5

按user_id分组，然后按游戏分组，最大（百分比）

select user_id, game,max(completepercentage) from @table
where user_id = 1
group by user_id,game

如果您愿意，可以添加排序，但上面给出了所需的结果

Answer 6

此查询将帮助您获得每位用户百分比最高的游戏

SELECT g.user_id, g.game, g.CompletePercentage FROM 
games g 
INNER JOIN (
 SELECT user_id, game, CompletePercentage FROM games
 ORDER BY CompletePercentage DESC
) j ON g.user_id = j.user_id 
GROUP BY g.user_id

在分组之前，这是一种众所周知的排序方法。

选择金额最高的记录

6 个答案: