Question

我有一个如下所示的XML文件：

<Categories>
 <Category Name="Mobile">
  <SubCategory Name="Mobile Phones" MarkUp="1.2">
   <Mapping Category1="COMMUNICATION" Category2="PHONE" Category3="MOBILE" Category4="MOBILE PHONE" Category5="ANDROID" Category6="" Category7="" />
   <Mapping Category1="COMMUNICATION" Category2="PHONE" Category3="MOBILE" Category4="MOBILE PHONE" Category5="BLACKBERRY OS" Category6="" Category7="" />
   <Mapping Category1="COMMUNICATION" Category2="PHONE" Category3="MOBILE" Category4="MOBILE PHONE" Category5="OTHER" Category6="" Category7="" />
   <Mapping Category1="COMMUNICATION" Category2="PHONE" Category3="MOBILE" Category4="MOBILE PHONE" Category5="SYMBIAN" Category6="" Category7="" />
   <Mapping Category1="COMMUNICATION" Category2="PHONE" Category3="MOBILE" Category4="MOBILE PHONE" Category5="WINDOWS PHONE" Category6="" Category7="" />
  </SubCategory>
</Categories>

我目前正在反序列化：

[XmlRoot(ElementName = "Category")]
public class XmlCategory
{
    [XmlAttribute(AttributeName = "Name")]
    public string Name { get; set; }

    [XmlElement("SubCategory")]
    public XmlSubCategory[] XmlSubCategories { get; set; }
}

public class XmlSubCategory
{
    [XmlAttribute(AttributeName = "Name")]
    public string Name { get; set; }

    [XmlAttribute(AttributeName = "MarkUp")]
    public string MarkUp { get; set; }

    [XmlElement("Mapping")]
    public XmlMapping[] Mappings { get; set; }
}

public class XmlMapping
{   
    [XmlAttribute(AttributeName = "Category1")]
    public string Category1 { get; set; }
    // etc.
}

问题在于Mapping节点 - 我宁愿得到它的属性集合，然后为每个节点创建一个字符串 - 我不确定如何解决这个问题 - 我尝试过使用XmlAnyAttribute和XmlArrayItem < / p>

干杯

Answer 1

是的，你可以在这里使用XmlAnyAttribute，虽然我个人建议明确的成员方法是优越的，即你的

public class XmlMapping
{
    [XmlAttribute] public string Category1 { get; set; }
    [XmlAttribute] public string Category2 { get; set; }
    [XmlAttribute] public string Category3 { get; set; }
    [XmlAttribute] public string Category4 { get; set; }
    [XmlAttribute] public string Category5 { get; set; }
    [XmlAttribute] public string Category6 { get; set; }
    [XmlAttribute] public string Category7 { get; set; }
}

然而，这也有效：

public class XmlMapping
{
    [XmlAnyAttribute]
    public XmlAttribute[] Attributes { get; set; }
}

然后只列举它：

foreach (var map in subCat.Mappings)
{
    var attribs = map.Attributes;
    if (attribs != null)
    {
        foreach (var attrib in attribs)
        {
            System.Console.WriteLine("{0}={1}", attrib.Name, attrib.Value);
        }
    }
}

对我来说很好......（虽然我必须修复破碎的xml - 缺少一个结束标记）

C＃XML将所有属性反序列化为集合

1 个答案: