Question

我是一个肥皂网络服务提供的，它有一个带有soapaction =“”的wsdl

<wsdl:binding name="SimpleSearchRequestSoapBinding" type="impl:SimpleSearchRequest">
<wsdlsoap:binding style="document" transport="http://schemas.xmlsoap.org/soap/http"/>
<wsdl:operation name="getSearchResults"><wsdlsoap:operation **soapAction=""**/>
<wsdl:input name="getSearchResultsRequest">
<wsdlsoap:body use="literal"/></wsdl:input>
<wsdl:output name="getSearchResultsResponse">
<wsdlsoap:body use="literal"/></wsdl:output>
</wsdl:operation>

点击这样的网络服务：

SoapObject request = new SoapObject(OKMConstants.NAMESPACE, OKMConstants.OPERATION_NAME);        
             request.addProperty("searchParam","faq");

             SoapSerializationEnvelope soapEnvelope = new SoapSerializationEnvelope(SoapEnvelope.VER12);
             soapEnvelope.setOutputSoapObject(request);

             HttpTransportSE httpTransport = new HttpTransportSE(OKMConstants.url);

                         httpTransport.call("", soapEnvelope);        
        //   Object response =  soapEnvelope.getResponse();

             SoapObject result = (SoapObject)soapEnvelope.bodyIn;

但它的抛出异常：

org.xmlpull.v1.XmlPullParserException: Expected a quoted string (position:DOCDECL @1:62 in java.io.InputStreamReader@410b9d60)

Answer 1

你应该传递soapAction null（它将被ksoap2设置为空字符串）或传递带引号的空字符串： httpTransport.call("\"\"", soapEnvelope);

Answer 2

httpTransport.call（SOAPACTION，的SoapEnvelope）;

认为在这一行可能是问题，请尝试在call方法中使用soapAction。

Soap webservice没有给出响应

2 个答案: