Question

在这里，当我传递正确且不正确的值时，我得到的结果都是4

当我执行此查询时

select Count(*) into result 
from document_details 
where document_name = name 
and document_path = path;

然后它显示我正确答案是1。请尽快帮助我。提前谢谢!!

create procedure check_status(IN name INT(30),IN path INT(255))    
    BEGIN
    declare result int;
    set result = 0;
    select Count(*) into result from `document_details` where `document_name`=name and `document_path`=path;
    select result;

END

Answer 1

如果IF类型没问题，那么它应该不能工作，然后改为ie (name CHAR(30),path CHAR(255))

create procedure check_status(name INT(30),path INT(255))    
BEGIN

select Count(*) as result from `document_details` 
where `document_name`=name and     `document_path`=path;

END;

在程序中，函数中没有IN / OUT ......

mysql中存储过程中的参数

1 个答案: