Question

这是我的代码：

 <?php    
    //Set content-type header
    header("Content-type: image/png");

    //Include phpMyGraph5.0.php
    include_once('phpMyGraph5.0.php');
    include("koneksi.php");

    //Set config directives
    $cfg['title'] = 'Example graph';
    $cfg['width'] = 500;
    $cfg['height'] = 250;


    //Set data
    $query="select col1, col2 from tab1 where sub_project = 'sometext'";
    $result=mysql_query($query);
    $row = mysql_fetch_assoc($result);
    $data = array(
        $row['col1'] => $row['col2'],
    );

    //Create phpMyGraph instance
    $graph = new phpMyGraph();

    //Parse
    $graph->parseVerticalColumnGraph($data, $cfg);
?>

在我的情况下，col1中的数据是文本，而col2中的数据是数字。但是使用该代码，图表只显示第一行值。同时数据库中的值不止一个值。

Answer 1

在while循环中添加获取的结果，如下所示。

<?php    
    //Set content-type header
    header("Content-type: image/png");

    //Include phpMyGraph5.0.php
    include_once('phpMyGraph5.0.php');
    include("koneksi.php");

    //Set config directives
    $cfg['title'] = 'Example graph';
    $cfg['width'] = 500;
    $cfg['height'] = 250;


    //Set data
    $query="select col1, col2 from tab1 where sub_project = 'sometext'";
    $result=mysql_query($query);
    $data = array();
    while($row = mysql_fetch_assoc($result))
    {
       $data[$row['col1']] = $row['col2'];
    }

    //Create phpMyGraph instance
    $graph = new phpMyGraph();

    //Parse
    $graph->parseVerticalColumnGraph($data, $cfg);
?>

并且$data是多行的，并且包含来自DB的所有记录

希望此代码可以帮助您

PhpMygraph - 如何从数据库mysql中分配数组

1 个答案: