我必须解析一个数据包,该数据包存储在ascii代码的byte []中 byte [] user = new byte [] {112,114,97,116,121,117,115,104,0,0,0,0,45,50,51,0} 其中前12个字节是servername,后4个字节是id。
通过浏览之前的stackoverflow帖子,我想出了这段代码
[StructLayout(LayoutKind.Explicit)]
struct packetrf
{
public ulong servername
{
get
{
return (ulong)servername1 | ((ulong)servername2 << 8) | ((ulong)servername3 << 16) | ((ulong)servername4 << 24) | ((ulong)servername5 << 32) | ((ulong)servername6 << 40) | ((ulong)servername7 << 48) | ((ulong)servername8 << 56) | ((ulong)servername9 << 64) | ((ulong)servername10 << 72) | ((ulong)servername11 << 80) | ((ulong)servername12 << 88);
}
}
[FieldOffset(0)]
public byte servername1;
[FieldOffset(1)]
public byte servername2;
[FieldOffset(2)]
public byte servername3;
[FieldOffset(3)]
public byte servername4;
[FieldOffset(4)]
public byte servername5;
[FieldOffset(5)]
public byte servername6;
[FieldOffset(6)]
public byte servername7;
[FieldOffset(7)]
public byte servername8;
[FieldOffset(8)]
public byte servername9;
[FieldOffset(9)]
public byte servername10;
[FieldOffset(10)]
public byte servername11;
[FieldOffset(11)]
public byte servername12;
[FieldOffset(12)]
public Int32 imei_msn;
};
static private pack fromByte(byte[] arr)
{
pack str = new pack();
GCHandle handle = GCHandle.Alloc(arr, GCHandleType.Pinned);
str = (pack)Marshal.PtrToStructure(handle.AddrOfPinnedObject(), typeof(pack));
handle.Free();
return str;
}
static private void data_parser(byte[] pkt, int size, int indexno)
{
packetrf data = fromByte(pkt);
Console.WriteLine();
Console.WriteLine(data.servername);
Console.WriteLine(data.imei_msn);
Console.ReadKey();
}
public static void Main()
{
byte[] user = new byte[] {112, 114, 97, 116, 121, 117, 115, 104, 0, 0, 0, 0, 49, 50, 51, 0}
data_parser(user, 1, 2);
}
当我运行此代码时,我的输出为server name的7526488566770266736和imei_msn的13106,这可能是ascii-&gt; hex-&gt;十进制格式。现在我面临的问题是,如何将这些数字转换为某些意义的完整信息,例如第一个字符串显示名称,第二个字符串以十进制格式输入imei_msn?
答案 0 :(得分:2)
尝试使用固定大小的数组(请在此处阅读https://stackoverflow.com/a/14629106/613130)
[StructLayout(LayoutKind.Explicit)]
struct packetrf
{
[FieldOffset(0), MarshalAs(UnmanagedType.ByValArray, SizeConst=12)]
public byte[] servername;
[FieldOffset(12)]
public Int32 imei_msn;
};
然后从那里:
string serv = Encoding.ASCII.GetString(yourObject.servername).TrimEnd('\0');
或直接作为财产
public string serverName2
{
get
{
return Encoding.ASCII.GetString(servername).TrimEnd('\0');
}
}
请记住TrimEnd
'\0'
中所有byte[]
ASCII
。
您确定编码是àèéìòù
吗?尝试在名称中添加一些带重音的字母,例如UTF8
......也许它是Default
。或者它可能正在使用{{1}}编码。
答案 1 :(得分:0)
尝试将servername1
- servername12
个字节添加到byte[12]
数组中,然后使用
byte[] array = GetBytesOfServerName();
string serverName = Encoding.ASCII.GetString(array);
答案 2 :(得分:0)
如果您对项目使用/ unsafe没问题,可以使用这样的固定缓冲区:
[StructLayout(LayoutKind.Explicit)]
unsafe struct packetrf
{
[FieldOffset(0)]
public fixed byte[12] servername;
[FieldOffset(12)]
public Int32 imei_msn;
}
答案 3 :(得分:0)
这应该有效:
string serverName = Encoding.ASCII.GetString(user.Take(12).ToArray());
string imeiMsn = Encoding.ASCII.GetString(user.Skip(12).ToArray());
Console.WriteLine(serverName);
Console.WriteLine(imeiMsn);