我使用以下代码测试UsersController中的登录操作
public function testLogin() {
$data = array('User' => array(
'username' => 'hello',
'password' => '411'
)
);
$this->Users = $this->generate('Users',array('components'=> array('Auth','Session')));
$this->Users->Auth->staticExpects($this->once())
->method('user')
->with('id');
$this->testAction('/users/login', array('data' => $data, 'method' => 'post'));
}
,夹具是 -
class UserFixture extends CakeTestFixture {
public $import = array('model' => 'User', 'records' => true, 'connection' => 'fixture');
}
adn action is -
public function login() {
if($this->request->is('post')) {
if($this->Auth->login()) {
$this->redirect($this->Auth->redirect());
} else {
return false;
$this->Session->setFlash(__('Wrong Username Or Password,Please Try Again'));
}
}
}
始终显示
方法名称的期望失败等于1次调用时。 预计方法被调用1次,实际上被称为0次。
有什么问题?找不到任何解决方案,原因也是。请帮助。
答案 0 :(得分:2)
我认为模拟auth组件的问题是除了在组件数组中包含auth
之外,还需要指定要模拟的Auth的哪些方法,以及如何模拟它们。
我在测试中处理AuthComponent的方法是使用方法创建一个超类:_generateMockWithAuthUserId
,它可以模拟Auth组件,以及我需要的方式。
我从下面的超类中粘贴了代码。
class AppControllerTest extends ControllerTestCase {
public function setUp() {
parent::setUp();
$this->User = ClassRegistry::init('User');
}
public function tearDown() {
unset($this->User);
parent::tearDown();
}
public function testPlaceholder(){
// This just here so we don't get "Failed - no tests found in class AppControllerTest"
$this->assertTrue(true);
}
protected function _generateMockWithAuthUserId($contollerName, $UserId){
$this->authUserId = $UserId;
$this->authUser = $this->User->findById($this->authUserId);
$this->controller = $this->generate($contollerName, array(
'methods' => array(
'_tryRememberMeLogin',
'_checkSignUpProgress'
),
'components' => array(
'Auth' => array(
'user',
'loggedIn',
),
'Security' => array(
'_validateCsrf',
),
'Session',
)
));
$this->controller->Auth
->expects($this->any())
->method('loggedIn')
->will($this->returnValue(true));
$this->controller->Auth
->staticExpects($this->any())
->method('user')
->will($this->returnCallback(array($this, 'authUserCallback')));
}
public function authUserCallback($param){
if(empty($param)){
return $this->authUser['User'];
} else {
return $this->authUser['User'][$param];
}
}
}
然后这是一个继承自该超类的类的示例。记下它在何处/如何调用_generateMockWithAuthUserId
。基本上,这样做会设置一个合适的控制器,并使用Auth模拟相应的用户ID。
<?php
require_once dirname(__FILE__) . DS . 'AppControllerTest.php';
class EmployeeNotesControllerTestCase extends AppControllerTest {
public $fixtures = array(
// your fixtures go here
);
public function setUp() {
parent::setUp();
$this->EmployeeNote = ClassRegistry::init('EmployeeNote');
}
public function tearDown() {
unset($this->EmployeeNote);
parent::tearDown();
}
public function testSupervisorIndexCanNotSeeNotesOnSelf() {
$authUserId = 1;
$this->_generateMockWithAuthUserId('EmployeeNotes', $authUserId);
$this->controller->Session
->expects($this->once())
->method('setFlash');
$result = $this->testAction('supervisor/employee_notes/index/'.$authUserId, array('return' => 'vars', 'method' => 'get'));
$this->assertTrue(empty($result['employeeNotes']));
}
}
希望有所帮助。
答案 1 :(得分:0)
我找到了解决方案。工作正常。
public function testLogin() {
$data = array('User' => array(
'username' => 'sasa',
'password' => '111'
)
);
$this->Users = $this->generate('Users', array());
$result = $this->testAction('/users/login', array('data' => $data, 'method' => 'post'));
$this->assertEquals($data['User']['username'],$this->Users->Session->read('Auth.User.username'));
$result = $this->testAction('/users/logout');
}