我有一个对象'content',它与图片有很多关系(图片模型)。一切正常,直到我坚持(图像上传,移动到适当的文件夹,工作正常)。 persist命令返回以下错误:
在关联Creator \ MainBundle \ Entity \ Content#pictures上找到Symfony \ Component \ HttpFoundation \ File \ UploadedFile类型的实体,但期待Creator \ MainBundle \ Entity \ Picture
我理解错误意味着什么,它期待Picture对象而不是上传的文件对象。我不明白从哪里开始,我读过的所有文档都只显示了如何将单个文件上传到单个列。
图片模型只有一个字段:file(string)。
非常感谢任何帮助。
内容控制器代码:
$form = $this->createFormBuilder($content, array('validation_groups'=>array('upload_'.$type)))
->add('picture')
->add('Upload '.ucfirst($type), 'submit')
->getForm();
$form->handleRequest($request);
if($request->getMethod()=='POST' && $form->isvalid())
{
$content->uploadPicture();
$em->persist($content);
$em->flush();
$session = $request->getSession();
$session->getFlashBag()->add('success', 'Upload successful');
}
内容模型代码:
public function addPictures($picture)
{
$this->pictures[] = $picture;
return $this;
}
public function getPicture()
{
return $this->picture;
}
public function setPicture($picture)
{
$this->picture = $picture;
return $this;
}
public function getPictures()
{
return $this->pictures;
}
public function setPictures($pictures)
{
$this->pictures = $pictures;
return $this;
}
public function uploadPicture()
{
if (null === $this->getPicture()) {
return;
}
$extension = $this->getPicture()->getExtension();
if(!$extension) $extension = 'jpg';
// unique file name
$fname = uniqid().'.'.$extension;
$this->getPicture()->move(
$this->getUploadRootDir(),
$fname
);
$this->makeThumbnail($fname, $extension);
$this->addPictures($this->getPicture());
}
答案 0 :(得分:1)
好的,我想出来了..
$picture = new Picture();
$form = $this->createFormBuilder($picture)
->add('file')
->add('Upload Picture', 'submit')
->getForm();
$form->handleRequest($request);
if($request->getMethod()=='POST' && $form->isvalid())
{
$picture->uploadFile();
$em->persist($picture);
$content->addPicture($entity);
$em->persist($content);
$em->flush();
}
将上传功能移动到图片实体..还要重命名内容实体中的几个功能,但如果有人试图复制我所做的事情,那么任何事情都不应该是显而易见的..现在它很有用并插入关系。< / p>