这就是问题,我想在xCode中绘制一个dinamic屏幕,这取决于从webServer传来的标签数量,是这样的......
for (int i = 0; i< [webserver.arraylabels count]; i++){
UILabel *label[i];
label[i] = [functions createLabel:[[webserver.arraylabels objectAtIndex:i] textLabel]
locationX:[webserver.arraylabels objectAtIndex:i] locationX]
locationY:[webserver.arraylabels objectAtIndex:i] locationY]
heightControl:[webserver.arraylabels objectAtIndex:i] heightControl]
widthControl:[webserver.arraylabels objectAtIndex:i] widthControl]
adjustmentControl:UIViewAutoresizingFlexibleRightMargin];
[cell addSubview:label[i]];
}
[functions createLabel ...]是一个函数,它返回一个UILabel对象类型......
如果我运行这个我得到一个错误,因为标签名称上的[i],我该怎么办?
提前感谢您的支持
答案 0 :(得分:0)
这要归功于H2CO3
NSMutableArray *arregloControles = [[NSMutableArray alloc]init];
for (int i = 0; i< [webserver.arraylabels count]; i++){
UILabel *control;
control = [functions createLabel:[[webserver.arraylabels objectAtIndex:i] textLabel]
locationX:[webserver.arraylabels objectAtIndex:i] locationX]
locationY:[webserver.arraylabels objectAtIndex:i] locationY]
heightControl:[webserver.arraylabels objectAtIndex:i] heightControl]
widthControl:[webserver.arraylabels objectAtIndex:i] widthControl]
adjustmentControl:UIViewAutoresizingFlexibleRightMargin];
[cell addSubview:control];
[arregloControles addObject:control];
}
并将其称为H2CO3建议:
UILabel *label = [arregloControles objectAtIndex:0]; //no casting required
或
UILabel *label = (UILabel*)[self.view viewWithTag: labelTag];