Question

这是我的xml的片段，

<e80:td941Grp>
<e80:td941KeyGrp>
<e80:membExchIdCod>XX445678</e80:membExchIdCod>
<e80:membExchIdNam>XX44567899123</e80:membExchIdNam>
</e80:td941KeyGrp>
<e80:td941Rec>
<e80:prodId>5AB</e80:prodId>
<e80:quoReqTot>0</e80:quoReqTot>
<e80:dCutLim>150</e80:dCutLim>
<e80:goodQuoReqResp>0</e80:goodQuoReqResp>
<e80:quoReqViol>0</e80:quoReqViol>
<e80:shtQuoPct>0.00</e80:shtQuoPct>
<e80:valQuoReqViol>0</e80:valQuoReqViol>
<e80:valQuoReqTot>0</e80:valQuoReqTot>
<e80:valGoodQuoReqResp>0</e80:valGoodQuoReqResp>
<e80:violPct>0.00</e80:violPct>
</e80:td941Rec>

这是我的代码，

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml.Linq;
using System.Xml.Serialization;

namespace WindowsFormsApplication1
{
public class td941Rec
{


    private string _prodID;
    private string _qouReqTot;
    private string _dCutLim;
    private string _goodQuoRepResp;
    private string _quoReqViol;
    private string _shtQuoPct;
    private string _valQuoReqViol;
    private string _ValQuoRepTot;
    private string _valGoodQuoReqResp;
    private string _violPct;


    public string prodID { get; set; }
    public string qouReqTot { get; set; }
    public string dCutLim { get; set; }
    public string goodQuoRepResp { get; set; }
    public string quoReqViol { get; set; }
    public string shtQuoPct { get; set; }
    public string valQuoReqViol { get; set; }
    public string ValQuoRepTot { get; set; }
    public string valGoodQuoReqResp { get; set; }
    public string violPct { get; set; }

}

public class td941Grp
{
    private string _td941;
    public string td941 { get { return _td941; } set { _td941 = value; } }

    public List<td941Rec> dataList = new List<td941Rec>();
}


class QoutePerformance
{



    public void xmltoExcel()
    {
        string xmlDoc  =        @"........xxxxx.xml";

        XDocument xdoc1 = XDocument.Load(xmlDoc);

        td941Grp objtd941 = new td941Grp();

List<td941Grp> listtd941 = (from _td941 in xdoc1.Element("e80:td941")
.Elements("e80:td941Grp")
select new td941Grp
{
td941 = _td941.Element("e80:td941Grp").Value,dataList = (from _record in _td941.
Element("e80:td941Grp").Elements("e80:td941Rec")
select new td941Rec
{
   prodID = _td941.Element("prodID").Value,
   qouReqTot = _td941.Element("qouReqTot").Value,


 }).ToList()


  }).ToList();







    }

我收到错误XmlException未处理“''''字符，十六进制值0x3A，不能包含在名称中。”

我对c＃相对较新，但在xml中总是新手所以任何帮助都会非常感激。

谢谢，

Answer 1

您无法使用.Element("e80:td941")

而是使用XNamespace：

XNamespace nsE80 = xmlDoc.GetNamespaceOfPrefix("e80");

... .Element(nsE80 + "td941")

Xml到列表代码出错。 '：'字符，十六进制值0x3A，不能包含在名称中

1 个答案: