考虑此查询:
SELECT DATE_FORMAT(t.date, "%Y") training_year,
COUNT(i.id) nb_trainees,
nb_canceled_trainings,
nb_done_trainings,
(nb_canceled_trainings / (nb_canceled_trainings + nb_done_trainings)) cancellation_rate
FROM (
SELECT COUNT(`trainings_trainings`.`id`) nb_canceled_trainings
FROM `trainings_trainings`
WHERE `trainings_trainings`.`id_status` = 5
AND DATE_FORMAT(`trainings_trainings`.`date`, "%Y") = training_year
) nct, (
SELECT COUNT(`trainings_trainings`.`id`) nb_done_trainings
FROM `trainings_trainings`
WHERE `trainings_trainings`.`id_status` IN (6, 7)
AND DATE_FORMAT(`trainings_trainings`.`date`, "%Y") = training_year
) ndt,
`trainings_inscriptions` i
INNER JOIN `trainings_trainings` t ON i.`id_training` = t.id
GROUP BY training_year;
问题是我在子查询中无法访问training_year。我怎么能这样做?
我的第一个尝试是移动SELECT部分中的子查询,但在这样做之后,我不能将这些子查询的别名用于cancellation_rate计算。
修改
我的结果是@ Jafar的查询和一些修改:
SELECT current_year, nb_trainees, nb_canceled_trainings, nb_done_trainings,
(nb_canceled_trainings / (nb_canceled_trainings + nb_done_trainings)) cancellation_rate,
(nb_trainees / nb_done_trainings) filling
FROM (
SELECT COUNT(CASE WHEN `t`.`id_status` = 5 THEN 1 END) nb_canceled_trainings,
COUNT(CASE WHEN `t`.`id_status` IN (6, 7) THEN 1 END) nb_done_trainings, (
SELECT COUNT(`ti`.`id`) nb_trainees
FROM `trainings_inscriptions` `ti`
INNER JOIN `trainings_trainings` `tt` ON `ti`.`id_training` = `tt`.`id`
WHERE DATE_FORMAT (`tt`.`date`, "%Y") = DATE_FORMAT (`t`.`date`, "%Y")
) nb_trainees, DATE_FORMAT (`t`.`date`, "%Y") current_year
FROM `trainings_trainings` `t`
GROUP BY DATE_FORMAT (`t`.`date`, "%Y")
) dummy;
这就是我得到的:
+------+----------+----------+------+--------+---------+
| year | trainees | canceled | done | ratio | filling |
+------+----------+----------+------+--------+---------+
| 2012 | 0 | 0 | 0 | NULL | NULL |
| 2013 | 58 | 0 | 2 | 0.0000 | 29.0000 |
| 2014 | 2 | 1 | 0 | 1.0000 | NULL |
+------+----------+----------+------+--------+---------+
答案 0 :(得分:0)
尝试像这样修改子查询
SELECT COUNT(`trainings_trainings`.`id`) nb_canceled_trainings,
DATE_FORMAT(`trainings_trainings`.`date`, "%Y") training_year
FROM `trainings_trainings`
WHERE `trainings_trainings`.`id_status` = 5
GROUP BY training_year
然后您可以在主查询的training_year
部分中使用别名的字段WHERE
。
答案 1 :(得分:0)
您可以在表名称的前面放置别名,并在子查询本身中使用它,如果您要引用外部表,那么最好选择该字段然后与外部表连接。
EDIT v2.0 更改了查询以获得所需的结果
SELECT YEAR,
TRAINEES,
NCT,
NDT,
NCT / (NCT + NDT) RATIO
FROM ( SELECT COUNT (CASE WHEN T.ID_STATUS = 5 THEN 1 END) NCT,
COUNT (CASE WHEN T.ID_STATUS IN (6, 7) THEN 1 END) NDT,
(SELECT COUNT (TI.ID) TRAINEES
FROM trainings_inscriptions TI
WHERE TI.id_training = T.ID)
TRAINEES,
DATE_FORMAT (T.date, "%Y") year
FROM trainings_trainings t
GROUP BY DATE_FORMAT (T.date, "%Y"))