Question

我只是想在CakePhp中测试ajax表单提交。我有下面的代码。但是ajax没有用。

chrome中的错误： POST http://localhost/john/Frontends/AjaxFormSubmit 500（内部服务器错误）

查看文件

 echo $this->Form->input('appendedInputButton',
         array('id'=>'url','name' => 'AjaxFormSubmit', 'type' => 'text')); 

 echo $this->Form->button('Convert',
         array('id' => 'Convert', 'type' => 'button'));

的jQuery

$(document).ready(function () {

    $('#Convert').on({
        'click': function () {
            var urlVal = $("#url").val();
            if (urlVal == '' || urlVal == 0) {
                $("#url").focus();
                return false;
            }

            $.ajax({
                url: 'http://localhost/john/Frontends/AjaxFormSubmit',
                cache: false,
                type: 'POST',
                success: function (data) {
                    alert(data);
                }
            });
        }
    });
});

控制器

App::uses('AppController', 'Controller');

class FrontendsController extends AppController {

    public $name = 'Frontends';
    public $uses = array();
    public $components = array('RequestHandler');
    public $helpers = array('Html', 'Form');


    public function index() {
        $this - > layout = 'frontend_index_layout';
    }

    public function AjaxFormSubmit() {
        echo "Receiving Via Ajax";
    }
}

错误日志文件

2013-08-13 13:41:43 Error: [MissingControllerException] Controller class JsController could not be found.
Exception Attributes: array (
  'class' => 'JsController',
  'plugin' => NULL,
)
Request URL: /john/js/jquery-1.10.1.min.map
Stack Trace:
#0 G:\wamp\www\john\app\webroot\index.php(111): Dispatcher->dispatch(Object(CakeRequest), Object(CakeResponse))
#1 {main}
2013-08-13 13:42:01 Error: [MissingViewException] View file "G:\wamp\www\john\app\View\Frontends\Ajax_Form_Submit.ctp" is missing.
Exception Attributes: array (
  'file' => 'G:\\wamp\\www\\john\\app\\View\\Frontends\\Ajax_Form_Submit.ctp',
)
Request URL: /john/Frontends/AjaxFormSubmit
Stack Trace:
#0 G:\wamp\www\john\lib\Cake\View\View.php(468): View->_getViewFileName(NULL)
#1 G:\wamp\www\john\lib\Cake\Controller\Controller.php(948): View->render(NULL, NULL)
#2 G:\wamp\www\john\lib\Cake\Routing\Dispatcher.php(194): Controller->render()
#3 G:\wamp\www\john\lib\Cake\Routing\Dispatcher.php(162): Dispatcher->_invoke(Object(FrontendsController), Object(CakeRequest), Object(CakeResponse))
#4 G:\wamp\www\john\app\webroot\index.php(111): Dispatcher->dispatch(Object(CakeRequest), Object(CakeResponse))
#5 {main}

Answer 1

阅读错误日志：

错误：[MissingViewException]查看文件缺少“G：\ wamp \ www \ john \ app \ View \ Frontends \ Ajax_Form_Submit.ctp”。异常属性：array（'file'=＆gt; 'G：\ wamp \ www \ john \ app \ View \ Frontends \ Ajax_Form_Submit.ctp'，）请求URL：/ john / Frontends / AjaxFormSubmit

问题非常明确：您的视图文件丢失，因此请创建它。我不知道你对它有什么样的答案，但你做的是错的。如果你想返回json read this section。

如果你真的想要回复一个字符串，你需要调用$ this-＆gt; _stop（）;回声之后。但是，实际上你应该返回一些带有正确消息的json对象，而不是返回一个没有意义的字符串，这可能是错误代码和状态，这样你的javascript就可以处理响应。

CakePHP Ajax请求不会发生内部服务器错误

1 个答案: