Question

我正在开发一个可以向web服务器发送不同文件的应用程序。我也想发送大文件，能够做到这一点我需要将文件分块。但是当我将文件发送到服务器时，没有上传任何内容。我不知道我是如何发送文件的错误，它在我的响应上给出了错误500（内部服务器错误）。我不认为服务器是问题，因为当我使用上传文件时它工作的multiPartEntity但是当我使用BufferedInputStream和DataOutputStream时它不起作用。请帮助我，告诉我的代码有什么问题，为什么它无法发送我的文件。这是我到目前为止：

        String samplefile = "storage/sdcard0/Pictures/Images/picture.jpg";
        File mFile = new File(samplefile);

        int mychunkSize = 2048 * 1024;
        final long size = mFile.length();
        final long chunks = size < mychunkSize? 1: (mFile.length() / mychunkSize);

        int chunkId = 0;
        try {

            BufferedInputStream stream = new BufferedInputStream(new FileInputStream(mFile));

            String lineEnd = "\r\n";
            String twoHyphens = "--";
            String boundary =  "-------------------------acebdf13572468";// random data

            for (chunkId = 0; chunkId < chunks; chunkId++) {

                 URL url = new URL(urlString);

                 // Open a HTTP connection to the URL
                 HttpURLConnection conn = (HttpURLConnection) url.openConnection();

                 conn.setReadTimeout(20000 /* milliseconds */);
                 conn.setConnectTimeout(20000 /* milliseconds */);


                 // Allow Inputs
                 conn.setDoInput(true);
                 // Allow Outputs
                 conn.setDoOutput(true);
                 // Don't use a cached copy.
                 conn.setUseCaches(false);
                 // Use a post method.
                 conn.setRequestMethod("POST");

                 String encoded = Base64.encodeToString((_username+":"+_password).getBytes(),Base64.NO_WRAP); 
                 conn.setRequestProperty("Authorization", "Basic "+encoded); 
                 conn.setRequestProperty("Connection", "Keep-Alive");

                 conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
                 DataOutputStream dos = new DataOutputStream( conn.getOutputStream() );
                 dos.writeBytes(twoHyphens + boundary + lineEnd);

                 String param1 = ""+chunkId;
                 String param2 = ""+chunks;
                 String param3 = mFile.getName();
                 String param4 = samplefile;

              // Send parameter #file
                dos.writeBytes("Content-Disposition: form-data; name=\"fieldNameHere\";filename=\"" + param3 + "\"" + lineEnd); // filename is the Name of the File to be uploaded
                dos.writeBytes("Content-Type: image/jpeg" + lineEnd);
                dos.writeBytes(lineEnd);



                // Send parameter #chunks
                dos.writeBytes("Content-Disposition: form-data; name=\"chunk\"" + lineEnd);
                dos.writeBytes("Content-Type: text/plain; charset=UTF-8" + lineEnd);
                dos.writeBytes("Content-Length: " + param2.length() + lineEnd);
                dos.writeBytes(lineEnd);
                dos.writeBytes(param2 + lineEnd);
                dos.writeBytes(twoHyphens + boundary + lineEnd);


                // Send parameter #name
                dos.writeBytes("Content-Disposition: form-data; name=\"name\"" + lineEnd);
                dos.writeBytes("Content-Type: text/plain; charset=UTF-8" + lineEnd);
                dos.writeBytes("Content-Length: " + param3.length() + lineEnd);
                dos.writeBytes(lineEnd);
                dos.writeBytes(param3 + lineEnd);
                dos.writeBytes(twoHyphens + boundary + lineEnd);


                byte[] buffer = new byte[mychunkSize];

                stream.read(buffer);

                dos.write(buffer);

                dos.writeBytes(lineEnd);
                dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
                dos.flush();
                dos.close();


            }
        } catch (Exception e) {
            Log.e("Error Uploading Files", e.toString());
        }

Answer 1

您可以使用this代码。它是一个J2ME类，通过HTTP POST Multipart Requests处理文件上传。

希望这有帮助。

Answer 2

如果您愿意，可以使用此库。它非常容易实现并完成您所需的所有工作。

AndroidAsync

为什么它会在httpUrlConnection上返回内部服务器错误？

2 个答案: