Question

我正在尝试将此主要活动中的数据传递给另一个活动

我成功地在活动之间发送数据....就像从编辑文本到下一个活动的数据一样，通过putExtra和GetExtra方法并作为意图传递 < / p>

但我正面临着涉及这一特定任务的挑战将数据从listview发送到普通活动
数据在JSON的列表视图中填充，因此当点击a时行如何将该行的数据发送到新活动

任何想法，

ativity_main.xml

<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:tools="http://schemas.android.com/tools"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent" >

    <ListView
        android:id="@+id/listViewID"
        android:layout_width="fill_parent"
        android:layout_height="fill_parent" 

        android:layout_gravity="center">
    </ListView>

</LinearLayout>

MainActivity.java

public class MainActivity extends Activity {

    // url to make request
    private static String url = "http://54.218.73.244:7002/";
    List<Item> yourData = new ArrayList<Item>();

    ProgressDialog progressDialog;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        //Instantiating ProgressDialog with onCreate method
        progressDialog=new ProgressDialog(MainActivity.this);
        new ParsingAsync().execute();

    }

    private class ParsingAsync extends AsyncTask<Void, Void, Void>
    {

        @Override
        protected void onPreExecute() {
            // TODO Auto-generated method stub
            super.onPreExecute();
            progressDialog=ProgressDialog.show(MainActivity.this, "", "Please Wait", true, false);


        }

        @Override
        protected Void doInBackground(Void... params) {
            // TODO Auto-generated method stub

            // Creating JSON Parser instance
            JSONObjParser jParser = new JSONObjParser();

            // getting JSON string from URL
            JSONArray json = jParser.getJSONFromUrl(url);

            try {
                for (int i = 0; i < json.length(); i++) {
                    JSONObject c = json.getJSONObject(i);

                    // Storing each json item in variable
                    String NAME=c.getString("restaurantNAME");

                    yourData.add(new Item(NAME));
                }
            } catch (JSONException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }

            return null;
        }

        @Override
        protected void onPostExecute(Void result) {
            // TODO Auto-generated method stub
            super.onPostExecute(result);
            progressDialog.dismiss();
            ListView yourListView = (ListView) findViewById(R.id.listViewID);
            ListAdapter customAdapter = new ListAdapter(MainActivity.this, R.layout.itemlistrow, yourData);
            yourListView.setAdapter(customAdapter);
            yourListView.setOnItemClickListener(new OnItemClickListener() {

                @Override
                public void onItemClick(AdapterView<?> parent, View view,
                        int position, long id) {
                    // When clicked, show a toast with the TextView text
                    if(position == 0)
                    {
                        //code specific to first list item    
                        Intent myIntent = new Intent(MainActivity.this,CopperChimneyDesc.class);
                        startActivity(myIntent);
                    }else if(position == 1)
                    {
                        //Intent myIntent = new Intent(MainActivity.this,AroyDesc.class);
                        //startActivity(myIntent);                  
                    }

                }
            });
        }

    }

}

item.java

public class Item{
    private String Name;

    public Item(String name){
        this.Name = name;
    }
    public String getName(){
        return Name;
    }
}

谢谢，

Answer 1

好的，你会这样做

String item = yourData.get(position).getName();

然后，您可以使用以下内容将string添加到intent

intent.putExtra("restaurent", item);

另一方面，如果你要做textview

textView.setText(getIntent().getExtras().getString("restaurent"));

Answer 2

intent.putExtra("City Name", String.valueOf(lvCity.getSelectedItem()));

尝试这个演员。

Answer 3

您可以将数据保存在sharedPreferences中，并可以从其他活动中访问该数据。只是一个想法：）

Answer 4

您可以使用putextra方法包裹数据并将其发送到另一个活动。请参阅How to store values in onSaveInstanceState() and retrive?

Answer 5

由于您拥有用户点击的列表视图中项目的索引，您可以从适配器获取项目值：

String value = (String)customAdapter.getItem(position);
Intent myIntent = new Intent(MainActivity.this,CopperChimneyDesc.class);
intent.putExtra("restaurant_name", value);
startActivity(myIntent);

将活动从listview传递到另一个活动

5 个答案: