Question

我正在用PHP，MYSQL和HTML制作一个简单的博客。我在显示撇号和引号时遇到问题，而不是显示“示例”（在html页面中）它显示“示例”，我正在使用转义字符串而所有这些但它仍然无法正常工作:( 页面：

<?php
    $servidor = "XX";
    $bd = "XX";
    $usuario = "XX";
    $senha = "XX";

    mysql_connect($servidor, $usuario, $senha) or trigger_error(mysql_error());
    mysql_select_db('a3722962_main') or trigger_error(mysql_error());

    $tutoID = $_GET['tuto'];

    $query = mysql_query("SELECT * FROM tutorials WHERE id = '$tutoID'");

    while($line = mysql_fetch_array($query)) {
        $content          = $line['text'];
        $title            = $line['title'];
        $creator          = $line['creator'];
        $name             = $line['name'];
        $idtest           = $line['id'];
    }
    {echo "$content";}
?>

发布页面：

<?php
    mysql_connect($servidor, $usuario, $senha) or trigger_error(mysql_error());
    mysql_select_db('a3722962_main') or trigger_error(mysql_error());

    $usuario = mysql_real_escape_string($_SESSION['UsuarioNome']);
    $title = mysql_real_escape_string($_POST['title']);
    $post = mysql_real_escape_string($_POST['post']);
    $realname = $_SESSION['usuario'];
    $lang = $_POST['lang'];
    $cat = $_POST['cat'];
    $dopost = "INSERT INTO tutorials VALUES ('', '$title', '$post', '$usuario', '$realname', NOW( ), '$cat', '$lang')";

    if($title == "" or $post == "") {
        echo "<script>alert(Please, fill out the damn form...);
        location.href='inside' </script>";
    } else {
        echo "<script>alert(Your post probably has been added!); 
        location.href='inside'</script>";
    }

    if (!empty($_POST) AND (empty($post) OR empty($title))) {
        echo "<script>alert('Please fill out the damn posting form.'); 
        location.href='inside'</script>";
    } else {
        $query = mysql_query($dopost);
    };

    if($query) {
        echo "<script>alert('The post that you have just setup has been added successfully! :D');
        location.href='inside'</script>";
    } else {
        echo "Could not add this post to the database.";
        echo mysql_error();
    } 
?>

全部谢谢！

Answer 1

致电stripslashes

echo stripslashes($content);

撇号无法正确显示

1 个答案: