我正在尝试根据日期和时间对数组进行排序,我可以根据日期成功对数组进行排序,这两个时间都将作为字典中的另一个值。
所以日期是"yyyy-MM-dd"
格式的字符串,时间是格式为"HH:mm"
的字符串
时间值以键"starts"
的形式出现在字符串'“HH:mm”'格式中。
我知道我需要将两个字符串组合到'yyyy-MM-dd HH:mm'
但是如何?
-(NSMutableArray *)sortArrayBasedOndate:(NSMutableArray *)arraytoSort
{
NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:@"yyyy-MM-dd"];
NSComparator compareDates = ^(id string1, id string2)
{
NSDate *date1 = [formatter dateFromString:string1];
NSDate *date2 = [formatter dateFromString:string2];
return [date1 compare:date2];
};
NSSortDescriptor * sortDesc1 = [[NSSortDescriptor alloc] initWithKey:@"start_date" ascending:YES comparator:compareDates];
[arraytoSort sortUsingDescriptors:[NSArray arrayWithObjects:sortDesc1, nil]];
return arraytoSort;
}
知道如何解决这个问题?
答案 0 :(得分:9)
您还需要对时间进行排序,这就是sortUsingDescriptors:
采用数组的原因。
-(NSMutableArray *)sortArrayBasedOndate:(NSMutableArray *)arraytoSort
{
NSDateFormatter *fmtDate = [[NSDateFormatter alloc] init];
[fmtDate setDateFormat:@"yyyy-MM-dd"];
NSDateFormatter *fmtTime = [[NSDateFormatter alloc] init];
[fmtTime setDateFormat:@"HH:mm"];
NSComparator compareDates = ^(id string1, id string2)
{
NSDate *date1 = [fmtDate dateFromString:string1];
NSDate *date2 = [fmtDate dateFromString:string2];
return [date1 compare:date2];
};
NSComparator compareTimes = ^(id string1, id string2)
{
NSDate *time1 = [fmtTime dateFromString:string1];
NSDate *time2 = [fmtTime dateFromString:string2];
return [time1 compare:time2];
};
NSSortDescriptor * sortDesc1 = [[NSSortDescriptor alloc] initWithKey:@"start_date" ascending:YES comparator:compareDates];
NSSortDescriptor * sortDesc2 = [NSSortDescriptor sortDescriptorWithKey:@"starts" ascending:YES comparator:compareTimes];
[arraytoSort sortUsingDescriptors:@[sortDesc1, sortDesc2]];
return arraytoSort;
}
答案 1 :(得分:0)
将两者连接到一个时间戳。然后从参考日期开始获取TimeInterVal, 并按此号码排序