从多维数组中获取随机字符串

Question

以下是我的代码 我需要一个随机数组的单个字符串。

 string[,] array = new string[4,3]  { { "a1", "b1", "c1" }, {"a2", "b2", "c2" } , 
                                  { "a3", "b3", "c3" }, { "a4", "b4", "c4" } } ;

//string a =???
//string b =???
//string c =???

我需要的是a1，b1 c1或a2，b2，c2等......

任何想法都将受到赞赏..

谢谢， ARNAB

Answer 1

正如我所理解的那样，你想要获取你随机获得的行的列。 为此，只需在行索引上使用Math.Random()即可。在这种情况下数组[4]。

Answer 2

我强烈建议您使用jagged array。在这种情况下，您可以使用此扩展方法：

private static readonly Random _generator = new Random();

public static T RandomItem<T>(this T[] array)
{
    return array[_generator.Next(array.Length)];
}

像这样使用它：

string[][] array = new string[][] {
    new string[] { "a1", "b1", "c1" },
    new string[] { "a2", "b2", "c2" }, 
    new string[] { "a3", "b3", "c3" },
    new string[] { "a4", "b4", "c4" } };

string randomValue = array.RandomItem().RandomItem(); // b2 or c4 or ... etc.

一下子：

string[] randomValues = array.RandomItem(); // { "a3", "b3", "c3" } or ... etc.

或

string randomValues = string.Join(", ", array.RandomItem()); // a4, b4, c4

Why do i recommend is explained here

Answer 3

<击> 这将根据字符串

的第二个字符串对字符串进行分组

//http://stackoverflow.com/questions/3150678/using-linq-with-2d-array-select-not-found
string[,] array = new string[4,3]  { { "a1", "b1", "c1" }, {"a2", "b2", "c2" } , 
                                  { "a3", "b3", "c3" }, { "a4", "b4", "c4" } } ;

var query = from string item in array
            select item;

var groupby = query.GroupBy(x => x[1]).ToArray();

var rand = new Random();

//Dump is an extension method from LinqPad
groupby[rand.Next(groupby.Length)].Dump();

这将输出（随机）：

> a1,b1,c1

> a2,b2,c2

> a3,b3,c3

> a4,b4,c4

<击>

LOL，矫枉过正，没读过数组已经“按分组”索引......

http://www.linqpad.net/