Question

我想在php中比较两个数组。我的数组看起来像这样

Array ( 
[0] => Array ( [Id] => 1 [row1] => 1458)
[1] => Array ( [Id] => 2 [row1] => 16) 
[2] => Array ( [Id] => 3 [row1] => 115) 
[3] => Array ( [Id] => 4 [row1] => 18) 
[4] => Array ( [Id] => 5 [row1] => 13) 
[5] => Array ( [Id] => 6 [row1] => 13) 
[6] => Array ( [Id] => 7 [row1] => 131)
)

Array ( 
[0] => Array ( [Id] => 1 [row1] => 158)
[1] => Array ( [Id] => 2 [row1] => 165) 
[2] => Array ( [Id] => 3 [row1] => 111) 
[3] => Array ( [Id] => 4 [row1] => 186) 
[4] => Array ( [Id] => 5 [row1] => 3)
)

首先，array1大小和array2大小始终不相等。 array1中的Id值可能会或可能不会出现在array2中，如果该值不存在，则函数必须在array3中打印总索引，如

[someindex] => Array ( [Id] => 6 [row1] => 13 )

如果存在，函数应该将array1的row1减去array2的row1并在array3中打印，就像这样

[someindex] => Array ( [Id] => 1 [row1] => 1300)

我的最终输出应该是，

Array ( 
[0] => Array ( [Id] => 1 [row1] => 1300)
[1] => Array ( [Id] => 2 [row1] => -149) 
[2] => Array ( [Id] => 3 [row1] => 4) 
[3] => Array ( [Id] => 4 [row1] => -168) 
[4] => Array ( [Id] => 5 [row1] => 10) 
[5] => Array ( [Id] => 6 [row1] => 13) 
[6] => Array ( [Id] => 7 [row1] => 131)
)

任何人都可以帮我解决这个问题。

Answer 1

$arr1 = Array ( 
    0 => Array ('Id' => 1, 'row1' => 1458)
    ,1 => Array ('Id' => 2, 'row1' => 16) 
    ,2 => Array ('Id' => 3, 'row1' => 115) 
    ,3 => Array ('Id' => 4, 'row1' => 18) 
    ,4 => Array ('Id' => 5, 'row1' => 13) 
    ,5 => Array ('Id' => 6, 'row1' => 13) 
    ,6 => Array ('Id' => 7, 'row1' => 131)
);
$arr2 = Array ( 
    0 => Array('Id' => 1, 'row1' => 158)
    ,1 => Array('Id' => 2, 'row1' => 165) 
    ,2 => Array('Id' => 3, 'row1'=> 111) 
    ,3 => Array('Id' => 4, 'row1' => 186) 
    ,4 => Array('Id' => 5, 'row1' => 3)
);
$final = array();
foreach($arr1 as $k => $sec)
{
    $sub = 0;
    foreach($arr2 as $sec2)
    {
        if($sec2['Id']==$sec['Id'])
        {
            $sub = $sec2['row1'];
            break;
        }
    }
    $sec['row1'] -= $sub;
    //Or to save to another element:
    //$sec['row2'] = $sec['row1']-$sub;
    $final[] = $sec;
}

echo '<pre>'.print_r($final,true).'</pre>';

输出：

Array ( 
    [0] => Array ( [Id] => 1 [row1] => 1300)
    [1] => Array ( [Id] => 2 [row1] => -149) 
    [2] => Array ( [Id] => 3 [row1] => 4) 
    [3] => Array ( [Id] => 4 [row1] => -168) 
    [4] => Array ( [Id] => 5 [row1] => 10) 
    [5] => Array ( [Id] => 6 [row1] => 13) 
    [6] => Array ( [Id] => 7 [row1] => 131)
)

Answer 2

不知道这究竟是您想要的，但您可以检查array_key_exists是否存在密钥：

$array3 = array();
foreach ($array1 as $k => $v) {
        if (array_key_exists($k, $array2)) {
            $array3[] = $v - $array2[$k];
        } else {
            $array3[] = $v;
        }
    }

Answer 3

首先，您必须使用Id值作为键来搜索第二个数组，或者编写搜索功能。我选择前者：

$searchable = array_reduce($array2, function(&$result, $item) {
    return $result + array($item['Id'] => $item['row1']);
}, array());

array_reduce()函数以空数组开始，并使用数组加法运算符构建它;这将创建一个可以使用id解除引用的数组。

然后在第一个数组上执行映射操作：

$array3 = array_map(function($item) use ($searchable) {
    $value = isset($searchable[$item['Id']]) ? $searchable[$item['Id']] : 0;
    $item['row1'] -= $value;
//    $item['row2'] = $item['row1'] - $value;
    return $item;
}, $array1);

执行地图操作会保留原始数组，并使用您在回调函数中选择的值创建一个新数组。

Answer 4

这会创建一个索引数组（$new），以防主键与原始数组中的主键不匹配。

$arr = array ( 
    0 => array ( 'Id' => '1','row1' => 1458),
    1 => array ( 'Id' => '2','row1' => 16),
    2 => array ( 'Id' => '3','row1' => 115),
    3 => array ( 'Id' => '4','row1' => 18),
    4 => array ( 'Id' => '5','row1' => 13),
    5 => array ( 'Id' => '6','row1' => 13),
    6 => array ( 'Id' => '7','row1' => 131));
$arr2 = array ( 
    0 => array ( 'Id' => '1','row1' => 158),
    1 => array ( 'Id' => '2','row1' => 165),
    2 => array ( 'Id' => '3','row1' => 111),
    3 => array ( 'Id' => '4','row1' => 186),
    4 => array ( 'Id' => '5','row1' => 3));
$new = array();
foreach ($arr2 as $key => $value){
    $new[$value['Id']] = $value['row1'];
}
foreach ($arr as $key => $value){
    if (isset($new[$value['Id']])){
        $arr[$key]['row1'] -= $new[$value['Id']];
    }
}
print_r($arr);

在Php中进行数组比较，并在值中找到diff

4 个答案: