Question

我确实要求从指定地址中提取街道名称，邮政编码，城市，州，国家，纬度，经度

它适用于印度地址，当我尝试使用澳大利亚地址时，它无法检索街道名称和邮政编码其余的东西可以很好地从JSON数组中的地址组件中检索约束

我使用了以下代码，这些代码在Google开发人员论坛中引用

public void FrmGoogleGeoCode(string frmAddress)
{
        string addUrl = "http://maps.google.com/maps/api/geocode/json?address='" + frmAddress + "'&sensor=false";
      var result = new System.Net.WebClient().DownloadString(addUrl);
      GoogleGeoCodeResponse test = JsonConvert.DeserializeObject<GoogleGeoCodeResponse>(result);
      var response = test.results.First();  
}

在var结果中，我获取了地址组件和格式化地址的JSON数组从地址组件我需要从澳大利亚地址检索街道名称，城市，州，邮政编码和国家

请从此问题中取消阻止

提前致谢

Answer 1

感谢您的回复，我尝试了相同的地址，即澳大利亚悉尼新南威尔士州2000乔治街300号，但地址中没有回复

frmAddress ="300 George Street, Sydney NSW 2000, Australia";

这是我的以下代码，用于检索街道名称，城市，郊区，国家/地区，邮政编码

        string addUrl = "http://maps.google.com/maps/api/geocode/json?address='" + frmAddress + "'&sensor=false";
      var result = new System.Net.WebClient().DownloadString(addUrl);
      GoogleGeoCodeResponse test = JsonConvert.DeserializeObject<GoogleGeoCodeResponse>(result);
      var response = test.results.First();
      string route=null;
      string locality=null;
      string pstlCode = null;
      for (int i = 0; i < response.address_components.Count(); i++)
      {
          int j = 0;
          var components = response.address_components[i];
          string type = components.types[j].ToString();
          if (type == "route")
          {
              route = response.address_components[i].long_name.ToString();

          }
          if (type == "locality")
          {
           locality = response.address_components[i].long_name.ToString();
          }
          if (type == "postal_code")
          {
           pstlCode = response.address_components[i].long_name.ToString();
          }
      }
      frmLocation = route +","+locality +","+ pstlCode;

然后我用这段代码尝试了乔治街，悉尼，新南威尔士州，2000年，澳大利亚。

这是以下回复。请您发布代码，以便对我有所帮助。

{ "results" : [ {"address_components" : [
            {
               "long_name" : "George Street",
               "short_name" : "George Street",
               "types" : [ "colloquial_area", "political" ]
            },
            {
               "long_name" : "New South Wales",
               "short_name" : "NSW",
               "types" : [ "administrative_area_level_1", "political" ]
            },
            {
               "long_name" : "Australia",
               "short_name" : "AU",
               "types" : [ "country", "political" ]
            }
         ],
         "formatted_address" : "George Street, NSW, Australia",
         "geometry" : {
            "bounds" : {
               "northeast" : {
                  "lat" : -33.9134399,
                  "lng" : 151.1667177
               },
               "southwest" : {
                  "lat" : -34.0059442,
                  "lng" : 151.0332033
               }
            },
            "location" : {
               "lat" : -33.9547504,
               "lng" : 151.1053691
            },
            "location_type" : "APPROXIMATE",
            "viewport" : {
               "northeast" : {
                  "lat" : -33.9134399,
                  "lng" : 151.1667177
               },
               "southwest" : {
                  "lat" : -34.0059442,
                  "lng" : 151.0332033
               }
            }
         },
         "partial_match" : true,
         "types" : [ "colloquial_area", "political" ]
      }
   ],
   "status" : "OK"
}

无法通过反向地理编码使用谷歌检索街道，城市和国家澳大利亚地址

1 个答案: