Question

如何将选定的数据库放入第二页，然后插入另一个表中。

这是我的第一页：

    <?php
    session_start();

    $result = mysqli_query($con,"SELECT * FROM qwerty
    WHERE ID LIKE '$id' ");

while($row = mysqli_fetch_array($result))
  {
  echo "Name:" . $row['Fname'] . " " . $row['Lname'];
  } 

$_SESSION['fname']=$row['Fname'];
$_SESSION['lname']=$row['Lname']; 
?>

这是我的第二页：

<?php
session_start();


   $sql="INSERT INTO login (Fname, Lname)
    VALUES
    ('{$_SESSION['fname']}','{$_SESSION['lname']}')";

Answer 1

$sql="INSERT INTO login set
Fname='".$_SESSION['fname']."',
Lname='".$_SESSION['lname']."'";

Answer 2

请查看并尝试以下操作：

session_start();

$firstName = $_SESSION['fname'];
$lastName = $_SESSION['lname'];

$sql="INSERT INTO `login` (Fname, Lname)  VALUES ('$firstName','$lastName')";

同时确保填充会话时

while($row = mysqli_fetch_array($result))
  {
  echo "Name:" . $row['Fname'] . " " . $row['Lname'];
  } 

$_SESSION['fname']=$row['Fname']; //CHECK
$_SESSION['lname']=$row['Lname'];

分配了数据。也许在循环中添加它。如果您正在寻找最后一条记录，那么无论如何都会被记录：

while($row = mysqli_fetch_array($result))
  {
     echo "Name:" . $row['Fname'] . " " . $row['Lname'];

     $_SESSION['fname']=$row['Fname']; //CHECK
     $_SESSION['lname']=$row['Lname'];
  }

选择并插入无法在数据库库中保存会话

2 个答案: