我们有三个这样的数组,但这些都是动态的
Array
(
[04/07/2013] => 2
[05/02/2013] => 1
[06/02/2013] => 1
[08/07/2013] => 2
[08/08/2013] => 3
[09/07/2013] => 2
[11/07/2013] => 1
[16/03/2013] => 1
[17/07/2013] => 1
[18/04/2013] => 2
[18/07/2013] => 1
[21/05/2013] => 2
[24/05/2013] => 8
[25/04/2013] => 2
[26/04/2013] => 1
[26/06/2013] => 1
[30/05/2013] => 1
)
Array
(
[01/08/2013] => 42
[02/08/2013] => 2
[03/08/2013] => 3
[07/08/2013] => 29
[09/08/2013] => 4
[10/08/2013] => 4
[11/08/2013] => 31
[19/07/2013] => 4
[20/07/2013] => 4
[22/07/2013] => 13
[23/07/2013] => 69
[29/07/2013] => 4
[31/07/2013] => 5
)
Array
(
[13/02/2013] => 2
[26/04/2013] => 2
[04/06/2013] => 2
[20/06/2013] => 2
[04/07/2013] => 2
[09/07/2013] => 1
[01/08/2013] => 1
[07/08/2013] => 1
[08/08/2013] => 3
)
我们希望用键组合到其他数组中(键必须保持相同)。如果所有三个数组键都相同,则将其放入同一个键中另外明智地创建一个键,如果数组有其他明智的键,则将其设置为值它没有价值。
我们在这里尝试了这个
$maximum = max($countVisi,$countClic,$countClai);
if($countClic==$maximum){
$maxim = $clickArray;
}elseif($countVisi>=$maximum){
$maxim = $visitArray;
}elseif($countClai>=$maximum){
$maxim = $claimsArray;
}else{
$maxim = $visitArray;
}
我们计算最大索引数组并像这样预先循环
foreach($maxim as $key=>$values){
if($visitArray[$key]){
$vv[$key] = $visitArray[$key];
}else{
$vv[$key] = 0;
}
if($clickArray[$key]){
$cc[$key] = $clickArray[$key];
}else{
$cc[$key] = 0;
}
if($claimsArray[$key]){
$kk[$key] = $claimsArray[$key];
}else{
$kk[$key] = 0;
}
$combineArrayNext[$key][] = $vv[$key];
$combineArrayNext[$key][] = $cc[$key];
$combineArrayNext[$key][] = $kk[$key];
//$vvvvv = explode('/' , $key);
//$myKey[$key] = "'".date('d M Y' , strtotime($vvvvv[2]."/".$vvvvv[1]."/".$vvvvv[0]))."'";
}
问题是我们只是按照最大数组键获得。它保留了最大数组中不存在的键。
对不起解释,我想你理解我的问题。请与我们分享一些想法来解决我的问题。
由于
答案 0 :(得分:0)
希望此代码可以帮助您:
$dates = array_merge(array_keys($arr1), array_keys($arr2), array_keys($arr3));
foreach($dates as $date) {
$new_arr[$date] = array('click' => isset($arr1[$date])? $arr1[$date] : 0,
'visit' => isset($arr2[$date])? $arr2[$date] : 0,
'claim' => isset($arr3[$date])? $arr3[$date] : 0 );
}