如何路由包含查询字符串的DooPHP URI？

Question

我需要能够路由在查询字符串中传递信息的请求。例如，假设我的应用程序调用/ api / company / delete？id = 17。如何在DooPHP中进行路由？我已经定义了一个catchall路由，它正在抓住这个请求，但是我需要能够在没有捕获路径的情况下处理它们。

# this doesn't work
$route['get']['/api/company/delete?id=:id'] = array('AdminController', 'deletecompany');

# at the bottom of my routes I have this catchall route, which works but it catches --everything--
$route['*']['catchall']['/:id'] = array('HomeController', 'getregions'); 

我错过了一些明显的东西吗？

Answer 1

路由 $ route ['get'] ['/ api / company / delete /：id'] = array（'AdminController'，'deletecompany'）;

控制器 $这 - ＆GT; PARAMS [ 'ID']

或

路由 $ route ['post'] ['/ api / company / delete'] = array（'AdminController'，'deletecompany'）;

控制器 $ _POST [ 'ID']