我想刷新DbContext
的所有实体而不重新创建它,我尝试了以下内容,但没有一个是有意义的:
var context = ((IObjectContextAdapter)myDbContext).ObjectContext;
var refreshableObjects = (from entry in context.ObjectStateManager.GetObjectStateEntries(
EntityState.Added
| EntityState.Deleted
| EntityState.Modified
| EntityState.Unchanged)
where entry.EntityKey != null
select entry.Entity);
context.Refresh(RefreshMode.StoreWins, refreshableObjects);
//.......................................................................
foreach (var entry in this.Orm.ChangeTracker.Entries())
{
entry.State = EntityState.Unchanged;
}
this.Orm.ChangeTracker.DetectChanges();
唯一一个刷新DbContext
:
foreach (var i in this.Orm.ChangeTracker.Entries())
i.Reload();
但它太慢了。你能帮我选择正确的方法吗?
答案 0 :(得分:33)
我刚发现应该评估Enumerable
结果,因为Refresh
方法将其作为对象获取并且不对其进行评估。
var context = ((IObjectContextAdapter)myDbContext).ObjectContext;
var refreshableObjects = (from entry in context.ObjectStateManager.GetObjectStateEntries(
EntityState.Added
| EntityState.Deleted
| EntityState.Modified
| EntityState.Unchanged)
where entry.EntityKey != null
select entry.Entity).ToList();
context.Refresh(RefreshMode.StoreWins, refreshableObjects);
我更喜欢以下内容:
var refreshableObjects = myDbContext.ChangeTracker.Entries().Select(c=>c.Entity).ToList();
context.Refresh(RefreshMode.StoreWins, refreshableObjects);
答案 1 :(得分:13)
我检查了这个并且id工作正常:
//Search
Box box = dbContext.Boxes.FirstOrDefault(x => x.BoxId == 45);
//breakpoint here, change Name of Box by sql management studio
//Refresh
var context = ((IObjectContextAdapter)dbContext).ObjectContext;
context.Refresh(System.Data.Entity.Core.Objects.RefreshMode.StoreWins, box);
//Check refresh and if it is in context
box = dbContext.Boxes.FirstOrDefault(x => x.BoxId == 45);
您确定它是相同的db-context吗?
答案 2 :(得分:3)
using System.Data.Entity.Core.Objects;
using System.Data.Entity.Infrastructure;
using System.Linq;
namespace System.Data.Entity
{
public static class DbContextExtensions
{
/// <summary>
/// Refresh non-detached entities
/// </summary>
/// <param name="dbContext">context of the entities</param>
/// <param name="refreshMode">store or client wins</param>
/// <param name="entityType">when specified only entities of that type are refreshed. when null all non-detached entities are modified</param>
/// <returns></returns>
public static DbContext RefreshEntites(this DbContext dbContext, RefreshMode refreshMode, Type entityType)
{
//https://christianarg.wordpress.com/2013/06/13/entityframework-refreshall-loaded-entities-from-database/
var objectContext = ((IObjectContextAdapter)dbContext).ObjectContext;
var refreshableObjects = objectContext.ObjectStateManager
.GetObjectStateEntries(EntityState.Added | EntityState.Deleted | EntityState.Modified | EntityState.Unchanged)
.Where(x => entityType == null || x.Entity.GetType() == entityType)
.Where(entry => entry.EntityKey != null)
.Select(e => e.Entity)
.ToArray();
objectContext.Refresh(RefreshMode.StoreWins, refreshableObjects);
return dbContext;
}
public static DbContext RefreshAllEntites(this DbContext dbContext, RefreshMode refreshMode)
{
return RefreshEntites(dbContext: dbContext, refreshMode: refreshMode, entityType: null); //null entityType is a wild card
}
public static DbContext RefreshEntites<TEntity>(this DbContext dbContext, RefreshMode refreshMode)
{
return RefreshEntites(dbContext: dbContext, refreshMode: refreshMode, entityType: typeof(TEntity));
}
}
}
答案 3 :(得分:3)
在某些情况下,如果某个集合已由第三方应用更新,则刷新集合对象时可能无法重新加载该集合。
我遇到的情况是我有一个对象A,它与对象B有一对多的关系。
应用程序1加载A.ListB为空的对象A. 应用程序2填充A.ListB集合。 应用程序1重新加载对象A.
通过上述解决方案,A.ListB保持为空。我必须明确重新加载A.ListB集合。
以下是重新加载所有集合的通用方法:
var context = ((IObjectContextAdapter)this).ObjectContext;
// detach all added entities
ChangeTracker.Entries().Where(e => e.State == EntityState.Added).ToList().ForEach(e => e.State = EntityState.Detached);
// select entities
var refreshableObjects = ChangeTracker.Entries().Select(e => e.Entity).ToList();
// refresh each refreshable object
foreach (var @object in refreshableObjects)
{
// refresh each collection of the object
context.ObjectStateManager.GetRelationshipManager(@object).GetAllRelatedEnds().Where( r => r.IsLoaded).ToList().ForEach( c => c.Load() );
// refresh the object
context.Refresh(RefreshMode.StoreWins, @object);
}
答案 4 :(得分:1)
在数据库中插入后,我有一个触发器,并且正在事务中进行工作,因此我需要在相同的上下文中获取由触发器生成的新值。这对我有用:
using (var ctx = new context())
{
ctx.Connection.Open();
ctx.Transaction = ctx.Connection.BeginTransaction();
ctx.Entities.InsertOnSubmit(itemDB);
ctx.SubmitChanges();
ctx.Refresh(RefreshMode.OverwriteCurrentValues, itemDB);
Model newModel = itemDB.ToModel();
ctx.Transaction.Commit();
return newModel;
}
catch (Exception ex)
{
ctx.Transaction.Rollback();
}