C ++错误：预期标识符

Question

我正在尝试制作标题，但它给了我错误：

#ifndef __OFFSETS__H_
#define __OFFSETS__H_

typedef unsigned long MAIN = 0x22EA120;//0x022BF0C0 ;
typedef unsigned long RECOILVT = 0x020A3ACC;//0x020FA644;
typedef unsigned long DEVIATIONVT = 0x020A3AC8;//0x020FA640;

#define BF3_X                       
#define BF3_X_BASE                  
#define BF3_X_SIZE                  
#define OFFSET_CLIENTGAMECONTEXT    
#define OFFSET_BORDERINPUTNODE      
#define OFFSET_DXRENDERER           
#define OFFSET_GAMERENDERER         
#define pbcl_BASE                   
#define OFFSET_PBSS_BUFFER          
#define OFFSET_PBSS_TAKESS                 
#define OFFSET_GIVEDAMAGE           Address
#define OFFSET_COMPUTEAAB           0x010C95F0 // Function - BF3_X_BASE = IDA       
#define OFFSET_AABWORLDTRANSFORM    0x010C6610 // Function - BF3_X_BASE = IDA Address
#define OFFSET_DBGRENDERER2         0x00000000 // Function - BF3_X_BASE = IDA 
#define OFFSET_DBGRENDRAWTEXT       0x004B7610 // Function - BF3_X_BASE = IDA   
#define OFFSET_DBGRENDRAW2DLINE     0x004B9980 // Function - BF3_X_BASE = IDA 
#define OFFSET_DBGRENDRAWRECTLINE   0x004A11E0 // Function - BF3_X_BASE = IDA Address
#define OFFSET_DBGRENDRAWRECT           
#define OFFSET_DBGRENDRAWSPHERE     0x004B7610 // Function - BF3_X_BASE = IDA 
#define OFFSET_UPDATEMATRICES       0x006C3A90 // Function - BF3_X_BASE = IDA     
#define OFFSET_W2S                  0x00EF1590 // Function - BF3_X_BASE 
#define OFFSET_RS_BEGINDRAW         0x006800A1 // Function - BF3_X_BASE = IDA 
#define OFFSET_CLIENTPLAYER_ENTRY   0x00A99A20 // Function - BF3_X_BASE = IDA Address
#define OFFSET_CSW_GETWEAPON        0x01049B60 // Function - BF3_X_BASE = IDA 
#define OFFSET_CSW_GETHEAT          0x00000000 // Function - BF3_X_BASE = IDA 
#endif

错误是

error C2513: 'unsigned long' : no variable declared before '='

我不知道为什么？任何的想法 ？

Answer 1

这些行不正确

typedef unsigned long MAIN = 0x22EA120;//0x022BF0C0 ;
typedef unsigned long RECOILVT = 0x020A3ACC;//0x020FA644;
typedef unsigned long DEVIATIONVT = 0x020A3AC8;//0x020FA640;

您正在定义一种类型。你不能给类型赋值。

做其中一个！

修改

无论

A）

typedef unsigned long MAIN;
typedef unsigned long RECOILVT;
typedef unsigned long DEVIATIONVT;

或

b）中

#define MAIN 0x22EA120
#define RECOILVT 0x020A3ACC
#define DEVIATIONVT 0x020A3AC8

或

c）中

const int MAIN = 0x22EA120;//0x022BF0C0 ;
const int RECOILVT = 0x020A3ACC;//0x020FA644;
const int DEVIATIONVT = 0x020A3AC8;//0x020FA640;

您的选择

Answer 2

我认为你的意思是typedef unsigned long MAIN = 0x22EA120;或许是const unsigned long MAIN = 0x22EA120;//0x022BF0C0 ;？