Question

我的活动有很多活动 - 事件是活动发生的日期和时间。

在我的活动索引中，我想列出将来至少有一个活动的所有活动。

我正在使用ransack进行其他过滤，以类别等方式进行操作。

如何过滤关系中的大于条件？

我以为我能做到：

obj = search
        .joins(:event)
        .where(:events => ['end_at > ?', Date.today ])

但是我收到了错误：

undefined method `join' for #<Ransack::Search:0x007f8aa8eff918>

更新所以为了给出更多的背景，我的控制器看起来像这样

def index            
    if (params[:oldestchild].present? && params[:oldestchild].to_i > 0) ||   
      (params[:youngestchild].present? && params[:youngestchild].to_i > 0)
      @search = Activity
       .where(' (oldest > ?z and youngest < ?) or (oldest > ? and youngest < ?) ', 
         params[:oldestchild], params[:oldestchild],
         params[:youngestchild], params[:youngestchild], 
         )
       .search(params[:q])
    else
       @search = Activity
         .search(params[:q])
    end  

    @activities = Activity.filter(params, @search, request).includes(:provider).includes(:location)

    if current_parent and current_parent.children.first
      @min_child_age = current_parent.min_child_age 
      @max_child_age = current_parent.max_child_age
    end
end

我的模型有这个过滤方法：

  def self.filter(params, search, request)          
        obj = search.result(:distinct => true)      
#       obj = search
#               .joins(:event)
#               .where(:events => ['end_at > ?', Date.today ])      

    if params[:within].present? && (params[:within].to_i > 0)
          obj = obj.where(:location_id => self.build_locations_array(request))
        end                         
        if  params[:q].present? and params[:q][:category_ids].present? 
            obj = obj
            .joins(:categories)
            .where('categories.id' => params[:q][:category_ids])                                                                        
        end
        if params[:date_range] == "This month"              
            obj = obj.where(:start => (Date.today)..(Date.today.at_end_of_month))   
        end

        if params[:date_range] == "Next month"  
            date = Date.today + 1.month             
            obj = obj.where(:start => (date.at_beginning_of_month)..(date.at_end_of_month))                                                                     
        end
        if params[:date_range] == "Next 3 Months"               
            date = Date.today + 3.month             
            obj = obj.where(:start => (Date.today)..(date.at_end_of_month))                                                                     
        end
        if params[:date_range] == "Whenever"             
            obj = obj.where("start > ?",  Date.today)                                                                       
        end 

        obj.paginate(:page => params[:page],  :per_page => 5)               
  end

UPATE

一个正在运行的选项，但相当难看的是使用sql。

obj = search.result(:distinct => true)
 .where("exists (select events.id from events 
          where events.activity_id = activities.id 
          and end_at > ?)", Date.today)

Answer 1

解决方案似乎很简单：从if else语句中删除搜索（params [：q]）并在Activity.filter调用之后使用它（如果包含它们也会抛出相同的错误，则使用它）。

或者，或许更好：

obj = search.result(:distinct => true).joins(:event).where(:events => ['end_at > ?', Date.today ])

选择将来至少有一些has_many关系的记录

1 个答案: