Question

     FunWithScheduling fun = new FunWithScheduling();
     Console.WriteLine("This Is Your Scheduler");
     Console.WriteLine("What Do You Wish To Do");
     Console.WriteLine("Enter 1 To Add, 2 To Edit, 3 To Search And 4 To Exit");
     int Choice = Convert.ToInt32(Console.ReadLine());
     switch (Choice)
     {
              case 1:
                  goto fun.Add();
                  break;
              case 2:
                  goto fun.Edit();
                  break;
              case 3:
                  goto fun.Search();
                  break;
              case 4:
                  goto fun.Exit();
                  break;
             Default:
                   Console.WriteLine("Enter a Valid Number");   
                   return;
      }
 }

我有4个功能可以帮助我做以下事情加编辑搜索退出

我想使用switch case转到该功能。可能吗？它要求对象引用，然后是标签。

Answer 1

为什么不在没有goto的情况下调用方法？对我来说，这不是使用goto的正确方法，cfr MSDN Reference

这对我来说应该没问题：

FunWithScheduling fun = new FunWithScheduling();
 Console.WriteLine("This Is Your Scheduler");
 Console.WriteLine("What Do You Wish To Do");
 Console.WriteLine("Enter 1 To Add, 2 To Edit, 3 To Search And 4 To Exit");
 int Choice = Convert.ToInt32(Console.ReadLine());
 switch (Choice)
 {
          case 1:
              fun.Add();
              break;
          case 2:
              fun.Edit();
              break;
          case 3:
              fun.Search();
              break;
          case 4:
              fun.Exit();
              break;
         Default:
               Console.WriteLine("Enter a Valid Number");   
               return;
  }

}

Answer 2

删除goto。这些仅在您使用标签时使用。只需致电fun.Add()或fun.Edit()。等等

切换案例导致特定功能出现问题

2 个答案: