多个下拉列值插入单行而不是多行

时间:2013-08-10 05:04:58

标签: php javascript mysql

在这段代码中,当我从下拉列表中选择多个值时,它会在一行中存储,但我想在每一行中应用值,所以请任何人帮助我。 实际结果:

id    game
1.    cricket,football,tennis

期待结果:

id         game
1            cricket
2            football

代码 -

                <html>
                <body>
                  <?php
                     if(isset($_POST['submit']))
                     {
                    $query=mysql_connect('localhost','root','');
                       mysql_select_db("freeze",$query);
                       $choice=$_POST['game'];
                      $choice1=implode(',',$choice);
                      mysql_query("insert into tb values('','$choice1')");
                         }
                      ?>
                        <form method="post" action="multipleselect.php">
                           Select your favourite game:<br/>
                        <select name="game[]" multiple="multiple">
                              <option>Football</option>
                                   <option>Volleyball</option>
                                       <option>Badminton</option>
                                        <option>Cricket</option>
                                           <option>Cricket1</option>
                                             <option>Cricket2</option>
                                             <option>Cricket3</option>
                                                 <option>Cricket34</option>
                    </select>
             <input type="submit" name="submit">
                  </form>
                  </body>
                 </html>

4 个答案:

答案 0 :(得分:3)

首先,请不要使用mysql_*,因为它已弃用,请改用mysqli_PDO

现在如果您只想要选项的值,那么就像这样做

<select name="game[]" multiple="multiple">
      <option value="1">Football</option>
      <option value="2">Volleyball</option>
      ...
</select>
这样它就会给你1,2,....。希望这就是你要找的东西。

如果你正在寻找像这样的查询

INSERT INTO tb (`game`) VALUES ('Football'),('Volleyball')

假设id字段是自动递增的,则按如下方式更改代码:
HTML代码

<select name="game[]" multiple="multiple">
  <option>Football</option>
  <option>Volleyball</option>
  ...
</select>

php代码

$choice=$_POST['game'];   
$sql = "INSERT INTO tb (`game`) VALUES ";
$sqlValues= null;
foreach($choice as $ch) {
    $sqlValues .= "('$ch')," ;                     
}
$sql.=rtrim($sqlValues, ",");                      
echo $sql;
这样你就可以得到

id         game
1          cricket
2          football

答案 1 :(得分:1)

它会将它们全部插入一行,因为您正在摧毁$_POST['game']

$choice=$_POST['game'];
$choice1=implode(',',$choice);
mysql_query("insert into tb values('','$choice1')");

您需要遍历每个$_POST['game']

foreach($_POST['game'] as $choice){
    mysql_query("insert into tb values('','$choice')");
}

请注意,您的查询对SQL注入是开放的,请确保在插入数据库之前清理数据。另外,mysql_*已弃用,因此您应该更新为mysqliPDO - http://php.net/manual/en/mysqlinfo.api.choosing.php

答案 2 :(得分:0)

是否显示任何错误消息?在mysql_query语句之前插入以下代码:

echo "insert into tb values('','$choice1')";

正在展示什么?

答案 3 :(得分:0)

<?php
if(isset($_POST['submit']))
{
  $query=mysql_connect('localhost','root','');
  mysql_select_db("freeze",$query);
  $choice=$_POST['game'];
  $choice1=implode(',',$choice);
  foreach($choice1 as $choice) 
  {
     mysql_query("insert into tb values('','$choice')");
  }
}
?>

您只需尝试此代码,我希望它适合您。如果没有,请回复我。