Question

我见过多个人将一列列入逗号分隔列表的例子，但我还需要更多。

以下是我需要的数据和结果示例。

DECLARE @SalesPerson table (SalesPersonID int, SalesPersonName varchar(10))
DECLARE @Region table (RegionID int, RegionName varchar(15))
DECLARE @SalesPersonRegion table (SalesPersonID int, RegionID int)

INSERT INTO @SalesPerson (SalesPersonID, SalesPersonName) VALUES (1,'Jeff') 
INSERT INTO @SalesPerson (SalesPersonID, SalesPersonName) VALUES (2,'Pat') 
INSERT INTO @SalesPerson (SalesPersonID, SalesPersonName) VALUES (3,'Joe') 

INSERT INTO @Region (RegionID, RegionName) VALUES (1,'North') 
INSERT INTO @Region (RegionID, RegionName) VALUES (2,'South') 
INSERT INTO @Region (RegionID, RegionName) VALUES (3,'East') 
INSERT INTO @Region (RegionID, RegionName) VALUES (4,'West') 

INSERT INTO @SalesPersonRegion (SalesPersonID,RegionID) VALUES (1,1)
INSERT INTO @SalesPersonRegion (SalesPersonID,RegionID) VALUES (1,2)
INSERT INTO @SalesPersonRegion (SalesPersonID,RegionID) VALUES (1,3)
INSERT INTO @SalesPersonRegion (SalesPersonID,RegionID) VALUES (2,2)
INSERT INTO @SalesPersonRegion (SalesPersonID,RegionID) VALUES (2,3)
INSERT INTO @SalesPersonRegion (SalesPersonID,RegionID) VALUES (2,4)
INSERT INTO @SalesPersonRegion (SalesPersonID,RegionID) VALUES (3,1)
INSERT INTO @SalesPersonRegion (SalesPersonID,RegionID) VALUES (3,4)

一个简单的选择将为每个销售人员提供每个销售人员。

SELECT 
    sp.SalesPersonID,
    sp.SalesPersonName,
    r.RegionName
FROM @SalesPersonRegion spr
    JOIN @SalesPerson sp
        ON spr.SalesPersonID = sp.SalesPersonID
    JOIN @Region r
        ON spr.RegionID = r.RegionID

在这种情况下，它将返回9行。

我想得到这样的结果：

SalesPersonID    SalesPersonName      Regions
1                Jeff                 North,South,East
2                Pat                  South,East,West
3                Joe                  North,West

Answer 1

SELECT 
  sp.SalesPersonID, 
  sp.SalesPersonName, 
  Regions = STUFF
  (
    (
      SELECT ',' + r.RegionName
       FROM @Region AS r
       INNER JOIN @SalesPersonRegion AS spr
       ON r.RegionID = spr.RegionID
       WHERE spr.SalesPersonID = sp.SalesPersonID
       ORDER BY r.RegionID
       FOR XML PATH(''), TYPE
    ).value('.[1]','nvarchar(max)'),
    1,1,''
  )
FROM @SalesPerson AS sp
ORDER BY sp.SalesPersonID;

Answer 2

尝试此查询：

SELECT 
    sp.SalesPersonID,
    sp.SalesPersonName,
    reg.Regions
FROM @SalesPerson sp
    CROSS APPLY( -- or OUTER APPLY
        SELECT STUFF(
        (SELECT ','+r.RegionName
        FROM    @Region r INNER JOIN @SalesPersonRegion spr ON r.RegionID = spr.RegionID
        WHERE   spr.SalesPersonID = sp.SalesPersonID
        FOR XML PATH('')),1,1,'') AS Regions
    )reg;

结果：

SalesPersonID SalesPersonName Regions
------------- --------------- ----------------
1             Jeff            North,South,East
2             Pat             South,East,West
3             Joe             North,West

Answer 3

select
    sp.SalesPersonID,
    sp.SalesPersonName,
    stuff(
       (
           select ',' + r.RegionName
           from @SalesPersonRegion as spr 
               inner join @Region as r on r.RegionID = spr.RegionID
           where spr.SalesPersonID = sp.SalesPersonID
           for xml path(''), type
       ).value('.', 'nvarchar(max)')
       , 1, 1, '')
from @SalesPerson as sp

请参阅sql fiddle示例

将单个列连接到逗号分隔的列表中

3 个答案: