Question

我有一个包含服务器状态的表

create table ServerStatus
(
    ServerId int, 
    StartTime datetime, 
    Seconds int,
    [State] char(8) 
)

我想查询给定开始日期和结束日期将总结服务器在此期间每个州花费的时间。我还希望查询返回服务器在未知状态下花费的时间。

因此，例如对于以下数据

1   2008-01-01 00:00:00.000 120 broken  
1   2008-01-02 00:00:00.000 120 off     
1   2008-01-03 00:00:00.000 240 burning 
1   2008-01-04 00:00:00.000 60  off     
1   2008-01-05 00:00:00.000 60  off     
2   2008-01-01 00:00:00.000 60  broken  
2   2008-01-02 00:00:00.000 30  off     
2   2008-01-03 00:00:00.000 20  burning 
2   2008-01-04 00:00:00.000 600 off     
3   2007-01-04 00:00:00.000 600 off     
4   2007-12-12 00:00:00.000 999999999   onfire

提供范围。

select  @start = dateadd(second, 60, '2008-01-01'), 
@fin = dateadd(second, 60, '2008-01-04')

我想返回结果：

1   broken      60
1   burning     240
1   off         180
1   unknown     258720
2   burning     20
2   off         90
2   unknown     259090
4   onfire      259200

这个问题与Combining split date ranges in a SQL query

有些关联

Answer 1

这是我迄今为止所提出的最好的结果：

declare @start datetime
declare @fin datetime 

select  @start = dateadd(second, 60, '2008-01-01'), @fin = dateadd(second, 60, '2008-01-04')

select ServerId, State, Total = sum(
    case when StartTime > @start and DateAdd(second, Seconds, StartTime) <= @fin
        then Seconds
    when StartTime < @start and DateAdd(second, Seconds, StartTime) <= @fin
        then DateDiff(second, @start, DateAdd(second, Seconds, StartTime)) 
    when StartTime < @start and DateAdd(second, Seconds, StartTime) >= @fin
        then DateDiff(second, @start, @fin)
    else 
        DateDiff(second,StartTime,@fin)
    end)
into #t
from ServerStatus 
where @start < dateadd(second, Seconds, StartTime) 
and @fin > StartTime
group by ServerId, State

insert #t
select ServerId, 'unknown', DateDiff(second, @start, @fin) - sum(Total) 
from #t 
group by ServerId
having DateDiff(second, @start, @fin) > sum(Total)

select * from #t 
order by ServerId, State

汇总SQL查询中的拆分范围

1 个答案: