我有这个脚本从数据库中提取.csv文件,该文件包含用户登录的不同本地的数据。 .csv文件是这样的:
"id_user";"id_local"
"1";""
"2";"2,3,4"
"3";""
"5";"2,5"
"10";""
"13";"2"
"14";"5"
"15";"2"
"16";"1"
"20";"2"
"21";""
如您所见,每个用户可获得一个注册表 但是,要正确操纵它,我们需要这样:
"id_user";"id_local"
"2";"2"
"2";"3
"2";"4"
"5";"2"
"5";"5"
"13";"2"
"14";"5"
"15";"2"
"16";"1"
"20";"2"
因此,我需要创建一个删除没有本地用户的函数,并在不同的寄存器中拆分同一用户的不同本地。有谁知道我该怎么做?
这是我到目前为止的代码,但我不确定我是否采用了正确的方式:
function fix_local_secundario(){
$filename = "local_secundario.csv";
$file_locais = file_get_contents($filename);
$locais = explode("\n", $file_locais);
// $pattern = "/,/";
// $replacement = "\"\n;\"";
while ($line = current($locais)) {
$line = str_getcsv($line, ';', '"','\n');
// $line = preg_replace($pattern, $replacement, $line);
var_dump($line);
echo "\n";
next($locais);
}
}
答案 0 :(得分:0)
试试这个,看看是否有效:
function fix_local_secundario(){
$filename = "local_secundario.csv";
$file_locais = file_get_contents($filename);
$locais = explode("\n", $file_locais);
while ($line = current($locais)) {
// do first split on ; character
$arr1 = explode(";", $line);
// if the part after ; is not empty for this line
if ($arr1[1]!='""'){
// split it further on , character
$arr2 = explode(",", $arr1[1]);
foreach ($arr2 as $key => $val){
if($val[0] != '"'){
$val = '"'.$val;
}
if($val[strlen($val)-1] != '"'){
$val = $val . '"';
}
echo $arr1[0] . ";" . $val . "<BR>";
}
}
next($locais);
}
}
一旦这个基本部分正常工作,您应该将其更改为返回值而不是回显值,因为根据您的问题所做的更新,此代码是函数的一部分。
答案 1 :(得分:0)
这个怎么样......
$f = fopen("myfile.csv", "r");
while($row = fgetcsv($f, 0, ";")){
$locals = explode(",", $row[1]);
if (count($locals)>1){
foreach($locals as $local)
// iterate with $row[0] and $local
}elseif($row[1] != "")
// use $row[0] and $row[1]
}