Question

我有这个awk命令，我需要输入一个日期变量。我确定我在某处遗漏了一些语法。任何专家都可以帮助我吗？基本上，我需要根据脚本的运行时间来改变日期。

date=$(date --date="1 month ago" +"%d-%b-%Y")
wget -qO - http://*********/users.csv > users
awk      'NR==1          {print "Primary Comments,Customer Account Number,Transaction Date,Service Description,Quantity,Unit,Price,Service Category,PI\x27sName,Purchaser\x27s Last Name,Short Contributing Center Name,Resource Name,Line Item Assistant,Line Item Comments"}
          FNR==NR        {S[$1]=$2; P[$1]=$3; next}
          $1 in S        {print "Bruker 500 NMR",P[$1],date,"500 MHz",$2/60,"Hour","5","500 MHz",S[$1],$1,"","501 NMR","","" }
          ' FS="," OFS="," OFMT="%.2f" $date users FS=" " wtmp > billing-$inst-$date.csv

Answer 1

使用-v选项。

awk -v date="$date" ....

但是GNU awk（gawk）有自己的时间函数，这里记录了这些函数：http://www.gnu.org/software/gawk/manual/html_node/Time-Functions.html

将变量添加到awk命令

1 个答案: