Question

我很惊讶我无法找到解决方法。我们有一张桌子

ORDER #  |  PRODUCT ID  |  PRICE
   1     |     1        |   1.00
   1     |     2        |   2.00
   2     |     3        |   3.00
   2     |     4        |   4.00
   3     |     1        |   5.00
   3     |     4        |   6.00

我们希望捕获包含productID = 1的所有订单的收入总和。此示例中的结果应为1 + 2 + 5 + 6 = 14

实现这一目标的最佳方法是什么？

目前，我的最佳解决方案是运行两个查询 1 - SELECT orderID FROM table WHERE prodID=$prodID

2 - SELECT price FROM table WHERE orderID=[result of the above]

这已经奏效，但强烈希望只有一个查询。

Answer 1

这是一个查询，提供您要查找的结果：

SELECT OrderNum, SUM(PRICE) as TotalPrice
FROM MyTable AS M
WHERE EXISTS (SELECT 1 -- Include only orders that contain product 1
              FROM MyTable AS M2 
              WHERE M2.OrderNum=M.OrderNum AND M2.ProductId=1)
GROUP BY OrderNum

Answer 2

select sum(price) as total_price where product_id=[enter here id];

Answer 3

SELECT SUM(t1.price) FROM tableName t1 WHERE 
t1.orderId IN (SELECT t2.orderId FROM tableName t2 WHERE 
                t2.productId=productIdYouWant)

如果您需要更多关于这项工作的信息，请随时提出。

Answer 4

尝试：

select sum(price) as total_price
from orders
where prod_order in
       (select prod_order
       from orders
       where product_id = 1)

检查this SQLFiddle以确认结果。

Answer 5

您需要嵌套选择。内部选择应该为您提供总订单价值;

select order, sum(price) as totalvalue from table group by order

现在您需要选择产品编号为1的订单，并将订单价格加起来;

select sum(totalvalue) from (
  select order, sum(price) as totalvalue from table group by order
) where order in (
  select order from table where productid = 1
)

SQL查询 - 包含项的顺序总和

5 个答案: