我在mysql db中存储复选框值时遇到问题(只有最后一个值存储在数据库中)。 如何修复此代码以存储所有选中的值?
<label class="q" for="q1">Which, if any, of these activities did you do on the Internet in the last 30 days?
</label><br><br>
<input name="q1[]" type="checkbox" value="a1">Used e-mail<br>
<input name="q1[]" type="checkbox" value="a2">Used instant messenger & chat room<br>
<input name="q1[]" type="checkbox" value="a3">Made a purchase for personal use<br>
<input name="q1[]" type="checkbox" value="a4">Downloaded/Played a video game<br>
<input name="q1[]" type="checkbox" value="a5">Obtained news/information/current events<br>
<input name="q1[]" type="checkbox" value="a6">Looked for employment (Used classified listings)<br>
<input name="q1[]" type="checkbox" value="a7">Looked for recipes<br>
<input name="q1[]" type="checkbox" value="a8">Downloaded a movie<br>
<br>
<?php
include('config.php');
$tbl_name="temp_members_db";
$q1=$_POST['q1'];
$sql="INSERT INTO $tbl_name(q1)VALUES('$q1')";
?>
答案 0 :(得分:11)
您可以使用implode
http://php.net/manual/en/function.implode.php
$q1=implode(',', $_POST['q1']);
答案 1 :(得分:3)
<html>
<head><title>Example</title></head>
<body>
<form action="" method="post">
<table width="50%">
<tr>
<td><input type="checkbox"name="boxes[]"value="8am">1</input></td>
<td>8am</td>
</tr>
<tr>
<td><inputtype="checkbox"name="boxes[]"value="9am">2</input></td>
<td>9am</td>
</tr>
<tr>
<td><input type="checkbox"name="boxes[]"value="10am">3</input></td>
<td>10am</td>
</tr>
</table>
<input type="submit" name="submit">
</form>
<?php
if(isset($_POST['submit'])){
require_once("config.php");
if(isset($_POST['boxes'])){
$t1=implode(',', $_POST['boxes']);
$s = "insert into new(time) values('$t1')";
$res=mysql_query($s);
if($res){
echo "insert success";
}else{
echo "error in inserting";
}
}
}
?>
</body>
</html>
请试试这个。
答案 2 :(得分:1)
我遇到了与复选框相同的问题implode()就像魅力一样。 对于单选按钮,您需要使用关联数组来使implode()起作用。
答案 3 :(得分:0)
但我认为为这些项创建一个新表引用主id。然后你可以动态处理这个: 我需要一个关于付款选项的复选框,例如:
<div class="form-group row">
<label for="default-input" class="col-md-2 control-label">Payment Options</label>
<div class="col-md-10">
<input name="pamentoptionsValue[]" id="checkbox-0" value="1" class="" type="checkbox">
<label for="checkbox-0" class="control-label"> Cash </label>
<input name="pamentoptionsValue[]" id="checkbox-1" value="2" class="" type="checkbox">
<label for="checkbox-1" class="control-label"> Visa </label>
<input name="pamentoptionsValue[]" id="checkbox-1" value="3" class="" type="checkbox">
<label for="checkbox-1" class="control-label"> MasterCard </label>
<input name="pamentoptionsValue[]" id="checkbox-1" value="4" class="" type="checkbox">
<label for="checkbox-1" class="control-label"> American </label>
<input name="pamentoptionsValue[]" id="checkbox-1" value="5" class="" type="checkbox">
<label for="checkbox-1" class="control-label"> Express</label>
<input name="pamentoptionsValue[]" id="checkbox-1" value="6" class="" type="checkbox">
<label for="checkbox-1" class="control-label"> Nexus</label>
</div>
</div>
&#13;
这用于不同的公司Id然后我就像这样存储它:
for($u=0;$u<count($_POST['pamentoptionsValue']);$u++){
$pamentoptionsValue =$_POST['pamentoptionsValue'][$u];
//$mdeceased =isset($_POST['mdeceased'])?$_POST['mdeceased']:null;
if($pamentoptionsValue==1){
$pamentoptionsName='Cash';
}elseif($pamentoptionsValue==2){
$pamentoptionsName='Visa';
}elseif($pamentoptionsValue==3){
$pamentoptionsName='MasterCard';
}elseif($pamentoptionsValue==4){
$pamentoptionsName='American';
}elseif($pamentoptionsValue==5){
$pamentoptionsName='Express';
}elseif($pamentoptionsValue==6){
$pamentoptionsName='Nexus';
}elseif($pamentoptionsValue==7){
$pamentoptionsName='bKash';
}elseif($pamentoptionsValue==8){
$pamentoptionsName='Payza';
}
if($pamentoptionsValue){
$query5 = "INSERT INTO pamentoptions (companyId,pamentoptionsDeleted,pamentoptionsCreatedBy,pamentoptionsValue,pamentoptionsName) VALUES ('$companyId','0','$companyCreatedBy','$pamentoptionsValue','$pamentoptionsName')";
$inserted_rows5 = $db->insert($query5);
}
}