连续生成随机枚举值而不会获得两次相同的值

时间:2013-08-09 11:33:45

标签: java random enums

我有一个我想要随机的enum团队。所以我有:

public enum Teams { TEAM1, TEAM2, TEAM3, TEAM4, TEAM5, TEAM6; }

然后我有一个随机方法来随机生成值:

public static Teams getRandomTeam() {
    return Teams.values()[(int) (Math.random() * Teams.values().length)];
}

这会返回一个随机生成的团队,但是我需要,一旦团队生成,说TEAM2,它就不能再生成了。

我正在使用:

System.out.println("The team is " + getRandomTeam());
System.out.println("The team is " + getRandomTeam());
System.out.println("The team is " + getRandomTeam());
System.out.println("The team is " + getRandomTeam());
System.out.println("The team is " + getRandomTeam());
System.out.println("The team is " + getRandomTeam());

(我知道这是错误的,因为它一遍又一遍地调用这个方法。

在我运行程序的那一刻,输出可能是:

团队是:TEAM2

团队是:TEAM2

团队是:TEAM4

团队是:TEAM2

团队是:TEAM3

团队是:TEAM2

但是我需要我的程序只输出一次enum值。 感谢

4 个答案:

答案 0 :(得分:10)

只需使用Collections.shuffle

List<Team> teams = new ArrayList<>();
Collections.addAll(teams, Team.values());
Collections.shuffle(teams);

答案 1 :(得分:5)

最好逐个收集和返回元素。

  private static List<Teams> tList;

  private static void regenerateList() {
      tList = new ArrayList<Teams>(Arrays.asList(Teams.values()));
      Collections.shuffle(tList);
  }

  public static Teams getRandomTeam() {
      if (tList.size() > 0) {
         return tList.remove(0);
      } else {
          //handle as you wish: return null or regenerate the list 
         regenerateList();
         return getrandomTeam();
      }
  }

答案 2 :(得分:1)

这个怎么样?这是递归的!

public static enum TEAMS {
    TEAM1, TEAM2, TEAM3, TEAM4, TEAM5, TEAM6;
}

TEAMS[] teams = TEAMS.values();
Random rnd = new Random();

public TEAMS getnextRandomTeam() {
    int indx = rnd.nextInt(teams.length);
    TEAMS t = teams[indx];
    teams[indx] = null;
    return t == null ? getnextRandomTeam() : t;
}

答案 3 :(得分:0)

使用Collections shuffle方法:

List<Teams> teams = new ArrayList<Teams>(Arrays.asList(Teams.values()));
int index = Integer.MAX_VALUE;

public Teams getRandomTeam() {
    if (index >= teams.size()) {
        Collections.shuffle(teams);
        index = 0;
    }
    return teams.get(index++);
}

此代码以随机顺序返回所有值,并在耗尽时重置列表以无限期地重复该过程。