如何转换为JSON

Question

我很难将这个PHP解析为JSON kan有人帮我解决了这个如何将这个PHP转换为JSON

$query = "SELECT SUM(total)  FROM account";
$result = mysql_query($query);

while($row = mysql_fetch_assoc($result))
{
echo $row['SUM(total)'];
}

Answer 1

尝试json_encode喜欢

$query = "SELECT SUM(total) as total  FROM account";
$result = mysql_query($query);
while($row = mysql_fetch_assoc($result))
{
    $new_arr[] = $row['total'];
}
echo json_encode($new_arr);

尽量避免使用mysql_*函数，因为它们已被弃用。请使用mysqli_*函数或PDO语句。

Answer 2

$query = "SELECT SUM(total) as t  FROM account";
$result = mysql_query($query);

while($row = mysql_fetch_assoc($result))
{
    $new_arr[] = $row['t'];
}
echo json_encode($new_arr);

Answer 3

在php中使用json_encode()函数。

检查参考here

while($row = mysql_fetch_assoc($result))
{
    $myArray[] = $row['SUM(total)'];
}
echo json_encode($myArray);

Answer 4

while($row = mysql_fetch_assoc($result))
{
    $new_arr[] = array("total"=>$row['SUM(total)']);
}
echo json_encode($new_arr);