要求是限制用户在数字/十进制编辑文本字段中输入不超过1的十进制值。也就是说,我还需要将数字输入限制为6个最大数字。例如。 999999.9
如果用户单独输入数字 - 那么我应该能够将用户限制为6位数Max,但应该允许“。”和十进制数(如果用户输入)。
我不确定,怎么做。任何帮助和参考都会有很大的帮助。
答案 0 :(得分:4)
也许有些实现类似于此?我很确定它可以进行很多优化!
EditText et;
.....
// force number input type on edittext
et.setRawInputType(InputType.TYPE_CLASS_NUMBER | InputType.TYPE_NUMBER_FLAG_DECIMAL);
et.addTextChangedListener(new CustomTextWatcher(et));
其中:
class CustomTextWatcher implements TextWatcher {
private NumberFormat nf = NumberFormat.getNumberInstance();
private EditText et;
private String tmp = "";
private int moveCaretTo;
private static final int INTEGER_CONSTRAINT = 6;
private static final int FRACTION_CONSTRAINT = 1;
private static final int MAX_LENGTH = INTEGER_CONSTRAINT + FRACTION_CONSTRAINT + 1;
public CustomTextWatcher(EditText et) {
this.et = et;
nf.setMaximumIntegerDigits(INTEGER_CONSTRAINT);
nf.setMaximumFractionDigits(FRACTION_CONSTRAINT);
nf.setGroupingUsed(false);
}
public int countOccurrences(String str, char c) {
int count = 0;
for (int i = 0; i < str.length(); i++) {
if (str.charAt(i) == c) {
count++;
}
}
return count;
}
@Override
public void afterTextChanged(Editable s) {
et.removeTextChangedListener(this); // remove to prevent stackoverflow
String ss = s.toString();
int len = ss.length();
int dots = countOccurrences(ss, '.');
boolean shouldParse = dots <= 1 && (dots == 0 ? len != (INTEGER_CONSTRAINT + 1) : len < (MAX_LENGTH + 1));
if (shouldParse) {
if (len > 1 && ss.lastIndexOf(".") != len - 1) {
try {
Double d = Double.parseDouble(ss);
if (d != null) {
et.setText(nf.format(d));
}
} catch (NumberFormatException e) {
}
}
} else {
et.setText(tmp);
}
et.addTextChangedListener(this); // reset listener
//tried to fix caret positioning after key type:
if (et.getText().toString().length() > 0) {
if (dots == 0 && len >= INTEGER_CONSTRAINT && moveCaretTo > INTEGER_CONSTRAINT) {
moveCaretTo = INTEGER_CONSTRAINT;
} else if (dots > 0 && len >= (MAX_LENGTH) && moveCaretTo > (MAX_LENGTH)) {
moveCaretTo = MAX_LENGTH;
}
try {
et.setSelection(et.getText().toString().length());
// et.setSelection(moveCaretTo); <- almost had it :))
} catch (Exception e) {
}
}
}
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
moveCaretTo = et.getSelectionEnd();
tmp = s.toString();
}
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
int length = et.getText().toString().length();
if (length > 0) {
moveCaretTo = start + count - before;
}
}
}
不是100%,但您可以将其作为基础并在其基础上构建;)
编辑:尝试在文本更改后抛光设置插入位置但是比我估计的更困难并且在每次输入字符后还原到最后设置插入符号。我把我开始使用的代码留给了插入符号,也许你可以改进它?
答案 1 :(得分:2)
上述答案中有一个小错误
我编辑了一个使用下面的代码。
import java.math.RoundingMode;
import java.text.NumberFormat;
import android.text.Editable;
import android.text.TextWatcher;
import android.widget.EditText;
public class DecimalTextWatcher implements TextWatcher {
private NumberFormat numberFormat = NumberFormat.getNumberInstance();
private EditText editText;
private String temp = "";
private int moveCaretTo;
private int integerConstraint;
private int fractionConstraint;
private int maxLength;
/**
* Add a text watcher to Edit text for decimal formats
*
* @param editText
* EditText to add DecimalTextWatcher
* @param before
* digits before decimal point
* @param after
* digits after decimal point
*/
public DecimalTextWatcher(EditText editText, int before, int after) {
this.editText = editText;
this.integerConstraint = before;
this.fractionConstraint = after;
this.maxLength = before + after + 1;
numberFormat.setMaximumIntegerDigits(integerConstraint);
numberFormat.setMaximumFractionDigits(fractionConstraint);
numberFormat.setRoundingMode(RoundingMode.DOWN);
numberFormat.setGroupingUsed(false);
}
private int countOccurrences(String str, char c) {
int count = 0;
for (int i = 0; i < str.length(); i++) {
if (str.charAt(i) == c) {
count++;
}
}
return count;
}
@Override
public void afterTextChanged(Editable s) {
// remove to prevent StackOverFlowException
editText.removeTextChangedListener(this);
String ss = s.toString();
int len = ss.length();
int dots = countOccurrences(ss, '.');
boolean shouldParse = dots <= 1 && (dots == 0 ? len != (integerConstraint + 1) : len < (maxLength + 1));
boolean x = false;
if (dots == 1) {
int indexOf = ss.indexOf('.');
try {
if (ss.charAt(indexOf + 1) == '0') {
shouldParse = false;
x = true;
if (ss.substring(indexOf).length() > 2) {
shouldParse = true;
x = false;
}
}
} catch (Exception ex) {
}
}
if (shouldParse) {
if (len > 1 && ss.lastIndexOf(".") != len - 1) {
try {
Double d = Double.parseDouble(ss);
if (d != null) {
editText.setText(numberFormat.format(d));
}
} catch (NumberFormatException e) {
}
}
} else {
if (x) {
editText.setText(ss);
} else {
editText.setText(temp);
}
}
editText.addTextChangedListener(this); // reset listener
// tried to fix caret positioning after key type:
if (editText.getText().toString().length() > 0) {
if (dots == 0 && len >= integerConstraint && moveCaretTo > integerConstraint) {
moveCaretTo = integerConstraint;
} else if (dots > 0 && len >= (maxLength) && moveCaretTo > (maxLength)) {
moveCaretTo = maxLength;
}
try {
editText.setSelection(editText.getText().toString().length());
// et.setSelection(moveCaretTo); <- almost had it :))
} catch (Exception e) {
}
}
}
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
moveCaretTo = editText.getSelectionEnd();
temp = s.toString();
}
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
int length = editText.getText().toString().length();
if (length > 0) {
moveCaretTo = start + count - before;
}
}
}
使用如下..
itemCostEditText.addTextChangedListener(new DecimalTextWatcher(itemCostEditText, 6, 2));
答案 2 :(得分:0)
您可以使用TextWatcher的afterTextChanged / onTextChanged方法来获取文本更改通知,并使用DecimalFormat格式化输入文本
http://developer.android.com/reference/java/text/DecimalFormat.html
http://developer.android.com/reference/android/text/TextWatcher.html