Question

我想只删除以下语句返回的行，我该怎么做？

  select usersernum,username,useremail 
    from core.appuser
   where usersernum in (
              select ch.usersernum
                from core.appusersession ch
               where ch.usersernum not in (
                          select usersernum
                            from (
                                       select max(starttime) as maxstarttime
                                            , usersernum
                                         from core.appusersession  vip
                                        where vip.starttime >= '2011-01-01 00:00:00'
                                     group by usersernum
                                 )
                     )
            group by usersernum
         )
order by useremail
       ;

Answer 1

您可以使用

DELETE  FROM core.appuser WHERE usersnum IN (
     select  usersernum 
       from  core.appuser
      where  usersernum in (
             select  ch.usersernum
               from  core.appusersession ch
              where  ch.usersernum not in (
                 select  usersernum from (
                     select  max(starttime) as maxstarttime, usersernum
                       from  core.appusersession  vip where vip.starttime>='2011-01-01 00:00:00' group by usersernum))
          group by  usersernum)
    order by  useremail);

Answer 2

您没有说明您正在运行的DB2平台或版本，但如果您使用的是DB2 9.7 for Linux，UNIX和Windows或更高版本，则可以使用超级便捷的“从选择中删除”：

delete from (
  select usersernum,username,useremail 
    from core.appuser
   where usersernum in (
              select ch.usersernum
                from core.appusersession ch
               where ch.usersernum not in (
                          select usersernum
                            from (
                                       select max(starttime) as maxstarttime
                                            , usersernum
                                         from core.appusersession  vip
                                        where vip.starttime >= '2011-01-01 00:00:00'
                                     group by usersernum
                                 )
                     )
            group by usersernum
         )
    order by useremail
);

Answer 3

有时退后一步并问自己，这里的真正目标是什么，“业务术语”或日常语言而不是SQL。

您的查询看起来有一堆不必要的图层。您真正想要做的就是删除所有非活动用户，即自2011年初以来尚未开始会话的用户。

DELETE  FROM core.appuser 
  WHERE usersernum NOT IN 
    ( SELECT DISTINCT usersernum
        FROM core.appusersession  
        WHERE starttime>='2011-01-01 00:00:00'
    );

不是那么简单吗？

如何从DB2中删除具有多个select的表中的行

3 个答案: