Question

我正在尝试使用上下文菜单来处理项目列表，如下所示，但我不确定如何将项目单击到列表名称时进行链接。包含＆gt;＆gt;＆gt;＆gt;＆gt;的行是我认为我错了。有人可以看看我做错了什么吗？这是我的Main_Acitivty：

import java.util.ArrayList;
import android.app.ListActivity;
import android.media.MediaPlayer;
import android.os.Bundle;
import android.view.ContextMenu;
import android.view.ContextMenu.ContextMenuInfo;
import android.view.MenuInflater;
import android.view.MenuItem;
import android.view.View;
import android.widget.AdapterView.AdapterContextMenuInfo;
import android.widget.ListView;
import android.widget.Toast;

public class MainActivity extends ListActivity {
private ArrayList<Sound> mSounds = null;
private SoundAdapter mAdapter = null;
static MediaPlayer mMediaPlayer = null;

public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
registerForContextMenu(getListView());
this.getListView().setSelector(R.drawable.selector);
//create a simple list
mSounds = new ArrayList<Sound>();
Sound s = new Sound();
s.setDescription("Anjels");
s.setSoundResourceId(R.raw.anjels);
mSounds.add(s);
s = new Sound();
s.setDescription("Aggro");
s.setSoundResourceId(R.raw.aggro);
mSounds.add(s);
s = new Sound();
s.setDescription("Axo");
s.setSoundResourceId(R.raw.axo);
mSounds.add(s);
s = new Sound();
s.setDescription("Basix");
s.setSoundResourceId(R.raw.basix);
mSounds.add(s);
s = new Sound();
s.setDescription("Bender");
s.setSoundResourceId(R.raw.bender);
mSounds.add(s);
s = new Sound();
s.setDescription("Blimp");
s.setSoundResourceId(R.raw.blimp);
mSounds.add(s);
mAdapter = new SoundAdapter(this, R.layout.list_row, mSounds);
setListAdapter(mAdapter);
}
@Override
public void onListItemClick(ListView parent, View v, int position, long id){
Sound s = (Sound) mSounds.get(position);
MediaPlayer mp = MediaPlayer.create(this, s.getSoundResourceId());
mp.start();

}@Override
public void onCreateContextMenu(ContextMenu menu, View v, ContextMenuInfo menuInfo) {
    super.onCreateContextMenu(menu, v, menuInfo);
    MenuInflater inflater = getMenuInflater();
    inflater.inflate(R.menu.context_menu, menu);
  }


public boolean onContextItemSelected(MenuItem item) {
    AdapterContextMenuInfo info = (AdapterContextMenuInfo) item.getMenuInfo();
    >>>>>>String[] names = getResources().getStringArray(mSounds);
    switch(item.getItemId()) {
    case R.id.setasnotification:
          Toast.makeText(this, "Applying " + getResources().getString(R.string.setas) +
                      " context menu option for " + names[(int)info.id],
                      Toast.LENGTH_SHORT).show();
          return true;
    default:
          return super.onContextItemSelected(item);
    }
}}

Answer 1

CHange String[] names = getResources().getString(R.array.?????);

到String[] names = getResources().getStringArray(R.array.?????);

您可以参考android docs on String Resources。

字符串数组资源示例：

XML file saved at res/values/strings.xml:

<?xml version="1.0" encoding="utf-8"?>
<resources>
    <string-array name="planets_array">
        <item>Mercury</item>
        <item>Venus</item>
        <item>Earth</item>
        <item>Mars</item>
    </string-array>
</resources>

要访问行星数组：

String[] names = getResources().getStringArray(R.array.planets_array);

我的ContextMenu中有一个简单的错误，有人可以把它整理出来吗？

1 个答案: