所以我在“编程谜题和代码高尔夫”中看到了这个聪明的主题: We're not strangers... 。最好的答案是PHP代码打印 Never Gonna Give You Up 的歌词。它只有543个字节。
我试图理解这个PHP代码,但我无法理解这是如何工作的。我认为这是基于语法的压缩,但我不知道如何使用未声明的常量,如
<?php range('-', T);
所以这是代码。这是如何工作的?
<?=str_replace(range('-',T),split(q,"
I justCannaLE?2Gotta >u=Msta=.q
Ng1Nlet? downNrun<rH=5desMt?N>cryNsayRoodbyeNtE< lie5hurt?q
We'T3n each@Jor s8lSg6r hear9<ch: but6;Lo7hyL7BInsideCe both3Cha9Ro: S
We3KeRa45we;QplBq1)O)NgiT, nPgiT
(GqiT? upq howFJeel:
q knowqmeq<= q
YHq8sqo qt's beenqingq'req aqndqmake? q yHq othMqAqay it
q wqDqellq I'mqGqouqIq fqLhq tqerq
NPq
(OohqeTrQqRSna q gqonqve"),"We; n7trangMsL8loT63Ke rules5s8d8I
AJull commit4nt'sChatFKink: of6CHldn'tRetKisJrom<ny@Ruy-/A= if?<sk 42DS'tLE 4?;Lo8bli=L7ee..
O,R1)O,R001)/-..");
答案 0 :(得分:7)
让我们逐个分析str_replace
参数。
range('-',T)
range()
函数返回一个数组,该数组的元素从第一个参数到第二个参数。字符由ASCII值考虑,因此结果为
Array
(
[0] => -
[1] => .
[2] => /
[3] => 0
[4] => 1
[5] => 2
[6] => 3
[7] => 4
[8] => 5
[9] => 6
[10] => 7
[11] => 8
[12] => 9
[13] => :
[14] => ;
[15] => <
[16] => =
[17] => >
[18] => ?
[19] => @
[20] => A
[21] => B
[22] => C
[23] => D
[24] => E
[25] => F
[26] => G
[27] => H
[28] => I
[29] => J
[30] => K
[31] => L
[32] => M
[33] => N
[34] => O
[35] => P
[36] => Q
[37] => R
[38] => S
[39] => T
)
为什么T
代替"T"
? PHP有一个错误,它使未定义的常量作为与常量名称具有相同内容的字符串进行评估。常量T
未定义,因此它与"T"
相同,后者为代码高尔夫目的保存了两个字符。 q
之后也是如此。如果服务器上有错误报告,则会显示有关未定义常量的警告。
split(q,"I justCannaLE?2Gotta >u=Msta=.q...");
这会将字符串拆分为q
个字符的数组。同样,这使得代码比使用数组文字更短。结果:
Array
(
[0] =>
I justCannaLE?2Gotta >u=Msta=.
[1] =>
Ng1Nlet? downNrun<rH=5desMt?N>cryNsayRoodbyeNtE< lie5hurt?
[2] =>
We'T3n each@Jor s8lSg6r hear9<ch: but6;Lo7hyL7BInsideCe both3Cha9Ro: S
We3KeRa45we;QplB
[3] => 1)O)NgiT, nPgiT
(G
[4] => iT? up
[5] => howFJeel:
[6] => know
[7] => me
[8] => <=
[9] =>
YH
[10] => 8s
[11] => o
[12] => t's been
[13] => ing
[14] => 're
[15] => a
[16] => nd
[17] => make?
[18] => yH
[19] => othM
[20] => A
[21] => ay it
[22] => w
[23] => D
[24] => ell
[25] => I'm
[26] => G
[27] => ou
[28] => I
[29] => f
[30] => Lh
[31] => t
[32] => er
[33] =>
NP
[34] =>
(Ooh
[35] => eTrQ
[36] => RSna
[37] => g
[38] => on
[39] => ve
)
最后一个参数是目标字符串。
"We; n7trangMsL8loT63Ke rules5s8d8I
AJull commit4nt'sChatFKink: of6CHldn'tRetKisJrom<ny@Ruy-/A= if?<sk 42DS'tLE 4?;Lo8bli=L7ee..
O,R1)O,R001)/-.."
如果您将数组作为needle和haystack传递给str_replace()
,则可以一次更换一个数组。为简单起见,我们只需将"We; n7trangMs"
作为taget字符串,然后从;
开始替换。用"7"
替换"8s"
后的第一步(第二个数组中的相应替换):
"We; n8strangMs"
然后将"8"
替换为"o "
"We; no strangMs"
带有";"
的 "'re"
"We're no strangMs"
带有"M"
的 "er"
"We're no strangers"
简而言之,它是一种基本的压缩算法,您可以在其中找到在原始文本中重复的字符序列,并用单个字符替换它们。解压缩时,该字符将替换为原始序列。通过迭代运行进度,您可以再次压缩一次压缩的文本("o s"
=&gt; "8s"
=&gt; "7"
)。
答案 1 :(得分:1)
试试吧!
假定未定义的常量是字符串。这是启用通知时的样子:
Notice: Use of undefined constant T - assumed 'T' in D:\www\htdocs\test\index.php on line 1
Notice: Use of undefined constant q - assumed 'q' in D:\www\htdocs\test\index.php on line 1
Deprecated: Function split() is deprecated in D:\www\htdocs\test\index.php on line 12
We're no strangers to love
You know the rules and so do I
[...]
Never gonna say goodbye
Never gonna tell a lie and hurt you