Question

{
    "status": "Success",
    "message": "Contents retrieved successfully",
    "name": {
        "1": "God",
        "2": "Goat"
    },
    "sites": {
        "1": "google",
        "2": "yahoo",
        "3": "bing"
    },
    "places": [
        "UK",
        "AU",
        "US"
    ],
    "images": {
        "1": {
            "1x": "http://3.bp.blogspot.com/-PPrUA_pcNyI/Udtx6v7MlvI/AAAAAAAADZA/6X2Qu-FcHtA/s320/Android+JSON+stream+data+parsing+example+using+Gson.png",
            "2x": "http://3.bp.blogspot.com/-PPrUA_pcNyI/Udtx6v7MlvI/AAAAAAAADZA/6X2Qu-FcHtA/s320/Android+JSON+stream+data+parsing+example+using+Gson.png"
        },
        "2": {
            "1x": "http://3.bp.blogspot.com/-PPrUA_pcNyI/Udtx6v7MlvI/AAAAAAAADZA/6X2Qu-FcHtA/s320/Android+JSON+stream+data+parsing+example+using+Gson.png",
            "2x": "http://3.bp.blogspot.com/-PPrUA_pcNyI/Udtx6v7MlvI/AAAAAAAADZA/6X2Qu-FcHtA/s320/Android+JSON+stream+data+parsing+example+using+Gson.png"
        },
        "3": {
            "1x": "http://3.bp.blogspot.com/-PPrUA_pcNyI/Udtx6v7MlvI/AAAAAAAADZA/6X2Qu-FcHtA/s320/Android+JSON+stream+data+parsing+example+using+Gson.png",
            "2x": "http://3.bp.blogspot.com/-PPrUA_pcNyI/Udtx6v7MlvI/AAAAAAAADZA/6X2Qu-FcHtA/s320/Android+JSON+stream+data+parsing+example+using+Gson.png"
        }
    }
}

我的班级

import java.util.Map;

public class Data {

    String status;
    String message;
    Map<String, String> name;
    Map<String, String> Sites;
    @Override
    public String toString() {
        return "Data [status=" + status + ", message=" + message
                + ", name=" + name + ", Sites=" + Sites
                + "]";
    }


}

此类为while检索站点和名称返回null值

Answer 1

名称和网站是JSONObjects no Arrays。 JSON中的任何对象都必须使用GSON在类中进行反序列化。

所以试试这个，

public class MyJson {
    String status;
    String message;

    Sites sites;
    List<String> places;
}

public class Sites {
    String 1;
    String 2;
    String 3;
}

等每个对象。对于数组，您可以使用List / Map。

要使用它，请拨打以下电话：

Gson gson = new Gson();
MyJson myJson = gson.fromJson(yourJsonString, MyJson.class);

Answer 2

JsonParser parser = new JsonParser();
JsonObject object = (JsonObject)parser.parse(yourString);

for (Map.Entry<String,JsonElement> entry : object.entrySet()) {
    JsonArray array = entry.getValue().getAsJsonArray();
    for (JsonElement elementJSON : array) {
        [...]
    }
}

如何使用Gson解析这种json String？

2 个答案: