我有执行不同操作的短代码,我想测量执行每个操作所需的时间。我在这里读到关于秒表课程,并希望优化我的时间测量。 我的函数调用了其他5个函数,我想在不声明的情况下测量每个函数:
stopwatch sw1 = new stopwatch();
stopwatch sw2 = new stopwatch();
etc..
我的功能看起来像这样:
public bool func()
{
....
func1()
func2()
....
....
func5()
}
有没有办法用一个秒表实例测量时间?
谢谢!
答案 0 :(得分:19)
使用委托将方法作为参数传递给函数。
这里我使用了Action Delegates,因为指定的方法没有返回值。
如果您的方法具有返回类型或参数,则可以使用功能代理
进行相应修改 static void Main(string[] args)
{
Console.WriteLine("Method 1 Time Elapsed (ms): {0}", TimeMethod(Method1));
Console.WriteLine("Method 2 Time Elapsed (ms): {0}", TimeMethod(Method2));
}
static long TimeMethod(Action methodToTime)
{
Stopwatch stopwatch = new Stopwatch();
stopwatch.Start();
methodToTime();
stopwatch.Stop();
return stopwatch.ElapsedMilliseconds;
}
static void Method1()
{
for (int i = 0; i < 100000; i++)
{
for (int j = 0; j < 1000; j++)
{
}
}
}
static void Method2()
{
for (int i = 0; i < 5000; i++)
{
}
}
}
通过使用它,您可以传递任何您想要的方法。
希望有所帮助!
答案 1 :(得分:6)
您需要的是秒表类的重新启动功能,如下所示:
public bool func()
{
var stopwatch = Stopwatch.StartNew();
func1();
Debug.WriteLine(stopwatch.ElapsedMilliseconds);
stopwatch.Restart();
func5();
Debug.WriteLine(stopwatch.ElapsedMilliseconds);
}
答案 2 :(得分:5)
是的,试试这个:
void func1()
{
Stopwatch sw = new Stopwatch();
sw.Start();
func1();
sw.Stop();
Console.Write(sw.Elapsed);
sw.Restart();
func2();
sw.Stop();
Console.Write(sw.Elapsed);
}
答案 3 :(得分:1)
你可以使用这个小班:
public class PolyStopwatch
{
readonly Dictionary<string, long> counters;
readonly Stopwatch stopwatch;
string currentLabel;
public PolyStopwatch()
{
stopwatch = new Stopwatch();
counters = new Dictionary<string, long>();
}
public void Start(string label)
{
if (currentLabel != null) Stop();
currentLabel = label;
if (!counters.ContainsKey(label))
counters.Add(label, 0);
stopwatch.Restart();
}
public void Stop()
{
if (currentLabel == null)
throw new InvalidOperationException("No counter started");
stopwatch.Stop();
counters[currentLabel] += stopwatch.ElapsedMilliseconds;
currentLabel = null;
}
public void Print()
{
if (currentLabel != null) Stop();
long totalTime = counters.Values.Sum();
foreach (KeyValuePair<string, long> kvp in counters)
Debug.Print("{0,-40}: {1,8:N0} ms ({2:P})", kvp.Key, kvp.Value, (double) kvp.Value / totalTime);
Debug.WriteLine(new string('-', 62));
Debug.Print("{0,-40}: {1,8:N0} ms", "Total time", totalTime);
}
}
像这样使用:
var ps = new PolyStopwatch();
ps.Start("Method1");
Method1();
ps.Stop();
// other code...
ps.Start("Method2");
Method2();
ps.Stop();
ps.Print();
如果呼叫互相跟随,您可以省略Stop()
ps.Start("Method1");
Method1();
ps.Start("Method2");
Method2();
ps.Print();
它适用于循环:
for(int i = 0; i < 10000; i++)
{
ps.Start("Method1");
Method1();
ps.Start("Method2");
Method2();
}
ps.Print();
答案 4 :(得分:0)
我使用:
void MyFunc()
{
Watcher watcher = new Watcher();
//Some call
HightLoadFunc();
watcher.Tick("My high load tick 1");
SecondFunc();
watcher.Tick("Second tick");
Debug.WriteLine(watcher.Result());
//Total: 0.8343141s; My high load tick 1: 0.4168064s; Second tick: 0.0010215s;
}
班级
class Watcher
{
DateTime start;
DateTime endTime;
List<KeyValuePair<DateTime, string>> times = new List<KeyValuePair<DateTime, string>>();
public Watcher()
{
start = DateTime.Now;
times.Add(new KeyValuePair<DateTime, string>(start, "start"));
endTime = start;
}
public void Tick(string message)
{
times.Add(new KeyValuePair<DateTime, string>(DateTime.Now, message));
}
public void End()
{
endTime = DateTime.Now;
}
public string Result(bool useNewLine = false)
{
string result = "";
if (endTime == start)
endTime = DateTime.Now;
var total = (endTime - start).TotalSeconds;
result = $"Total: {total}s;";
if (times.Count <2)
return result + " Not another times.";
else
for(int i=1; i<times.Count; i++)
{
if (useNewLine) result += Environment.NewLine;
var time = (times[i].Key - times[i - 1].Key).TotalSeconds;
var m = times[i];
result += $" {m.Value}: {time}s;";
}
return result;
}
}