?graph-fs

Question

我希望这会是一件简单的事，但我找不到任何可以做到的事情。

我只想获取给定文件夹/目录中的所有文件夹/目录。

例如：

<MyFolder>
|- SomeFolder
|- SomeOtherFolder
|- SomeFile.txt
|- SomeOtherFile.txt
|- x-directory

我希望得到一个数组：

["SomeFolder", "SomeOtherFolder", "x-directory"]

或上面的路径，如果它是如何服务...

上面已经存在的任何事情都可以做到吗？

Answer 1

这是this answer的一个较短的同步版本，可以列出当前目录中的所有目录（隐藏或不隐藏）：

const { lstatSync, readdirSync } = require('fs')
const { join } = require('path')

const isDirectory = source => lstatSync(source).isDirectory()
const getDirectories = source =>
  readdirSync(source).map(name => join(source, name)).filter(isDirectory)

Answer 2

感谢JavaScript ES6（ES2015）的语法功能，它是一个内容：

同步版

const { readdirSync, statSync } = require('fs')
const { join } = require('path')

const dirs = p => readdirSync(p).filter(f => statSync(join(p, f)).isDirectory())

Node.js 10+的异步版本（实验性）

const { readdir, stat } = require("fs").promises
const { join } = require("path")

const dirs = async path => {
  let dirs = []
  for (const file of await readdir(path)) {
    if ((await stat(join(path, file))).isDirectory()) {
      dirs = [...dirs, file]
    }
  }
  return dirs
}

Answer 3

使用路径列出目录。

function getDirectories(path) {
  return fs.readdirSync(path).filter(function (file) {
    return fs.statSync(path+'/'+file).isDirectory();
  });
}

Answer 4

递归解决方案

我来到这里寻找一种方法来获取所有子目录及其所有子目录等。在accepted answer的基础上，我写道：

const fs = require('fs');
const path = require('path');

function flatten(lists) {
  return lists.reduce((a, b) => a.concat(b), []);
}

function getDirectories(srcpath) {
  return fs.readdirSync(srcpath)
    .map(file => path.join(srcpath, file))
    .filter(path => fs.statSync(path).isDirectory());
}

function getDirectoriesRecursive(srcpath) {
  return [srcpath, ...flatten(getDirectories(srcpath).map(getDirectoriesRecursive))];
}

Answer 5

这应该这样做：

CoffeeScript（同步）

fs = require 'fs'

getDirs = (rootDir) ->
    files = fs.readdirSync(rootDir)
    dirs = []

    for file in files
        if file[0] != '.'
            filePath = "#{rootDir}/#{file}"
            stat = fs.statSync(filePath)

            if stat.isDirectory()
                dirs.push(file)

    return dirs

CoffeeScript（异步）

fs = require 'fs'

getDirs = (rootDir, cb) ->
    fs.readdir rootDir, (err, files) ->
        dirs = []

        for file, index in files
            if file[0] != '.'
                filePath = "#{rootDir}/#{file}"
                fs.stat filePath, (err, stat) ->
                    if stat.isDirectory()
                        dirs.push(file)
                    if files.length == (index + 1)
                        cb(dirs)

JavaScript（异步）

var fs = require('fs');
var getDirs = function(rootDir, cb) { 
    fs.readdir(rootDir, function(err, files) { 
        var dirs = []; 
        for (var index = 0; index < files.length; ++index) { 
            var file = files[index]; 
            if (file[0] !== '.') { 
                var filePath = rootDir + '/' + file; 
                fs.stat(filePath, function(err, stat) {
                    if (stat.isDirectory()) { 
                        dirs.push(this.file); 
                    } 
                    if (files.length === (this.index + 1)) { 
                        return cb(dirs); 
                    } 
                }.bind({index: index, file: file})); 
            }
        }
    });
}

Answer 6

或者，如果您能够使用外部库，则可以使用filehound。它支持回调，承诺和同步调用。

使用承诺：

const Filehound = require('filehound');

Filehound.create()
  .path("MyFolder")
  .directory() // only search for directories
  .find()
  .then((subdirectories) => {
    console.log(subdirectories);
  });

使用回调：

const Filehound = require('filehound');

Filehound.create()
  .path("MyFolder")
  .directory()
  .find((err, subdirectories) => {
    if (err) return console.error(err);

    console.log(subdirectories);
  });

同步通话：

const Filehound = require('filehound');

const subdirectories = Filehound.create()
  .path("MyFolder")
  .directory()
  .findSync();

console.log(subdirectories);

有关详细信息（和示例），请查看文档：{{3}}

免责声明：我是作者。

Answer 7

在node.js版本> = v10.13.0的情况下，如果将withFileTypes选项设置为true，则fs.readdirSync将返回fs.Dirent对象的数组。

因此您可以使用

const fs = require('fs')

const directories = source => fs.readdirSync(source, {
   withFileTypes: true
}).reduce((a, c) => {
   c.isDirectory() && a.push(c.name)
   return a
}, [])

Answer 8

getDirectories的异步版本，你需要async module：

var fs = require('fs');
var path = require('path');
var async = require('async'); // https://github.com/caolan/async

// Original function
function getDirsSync(srcpath) {
  return fs.readdirSync(srcpath).filter(function(file) {
    return fs.statSync(path.join(srcpath, file)).isDirectory();
  });
}

function getDirs(srcpath, cb) {
  fs.readdir(srcpath, function (err, files) {
    if(err) { 
      console.error(err);
      return cb([]);
    }
    var iterator = function (file, cb)  {
      fs.stat(path.join(srcpath, file), function (err, stats) {
        if(err) { 
          console.error(err);
          return cb(false);
        }
        cb(stats.isDirectory());
      })
    }
    async.filter(files, iterator, cb);
  });
}

Answer 9

使用fs-extra，它承诺异步fs调用，以及新的等待异步语法：

const fs = require("fs-extra");

async function getDirectories(path){
    let filesAndDirectories = await fs.readdir(path);

    let directories = [];
    await Promise.all(
        filesAndDirectories.map(name =>{
            return fs.stat(path + name)
            .then(stat =>{
                if(stat.isDirectory()) directories.push(name)
            })
        })
    );
    return directories;
}

let directories = await getDirectories("/")

Answer 10

 var getDirectories = (rootdir , cb) => {
    fs.readdir(rootdir, (err, files) => {
        if(err) throw err ;
        var dirs = files.map(filename => path.join(rootdir,filename)).filter( pathname => fs.statSync(pathname).isDirectory());
        return cb(dirs);
    })

 }
 getDirectories( myDirectories => console.log(myDirectories));``

Answer 11

使用 fs，路径模块可以获取该文件夹。这个用Promise。如果您将获得填充，您可以将 isDirectory（）更改为 isFile（） Nodejs--fs--fs.Stats。最后，您可以获取文件＆＃39;名称文件＆＃39; extname等Nodejs---Path

var fs = require("fs"),
path = require("path");
//your <MyFolder> path
var p = "MyFolder"
fs.readdir(p, function (err, files) {
    if (err) {
        throw err;
    }
    //this can get all folder and file under  <MyFolder>
    files.map(function (file) {
        //return file or folder path, such as **MyFolder/SomeFile.txt**
        return path.join(p, file);
    }).filter(function (file) {
        //use sync judge method. The file will add next files array if the file is directory, or not. 
        return fs.statSync(file).isDirectory();
    }).forEach(function (files) {
        //The files is array, so each. files is the folder name. can handle the folder.
        console.log("%s", files);
    });
});

Answer 12

此答案未使用诸如readdirSync或statSync之类的阻塞函数。它不使用外部依赖项，也不在回调地狱的深处发现自己。

相反，我们使用现代JavaScript便利性，例如Promises和async-await语法。异步结果被并行处理；不按顺序-

const { readdir, stat } =
  require ("fs") .promises

const { join } =
  require ("path")

const dirs = async (path = ".") =>
  (await stat (path)) .isDirectory ()
    ? Promise
        .all
          ( (await readdir (path))
              .map (p => dirs (join (path, p)))
          )
        .then
          ( results =>
              [] .concat (path, ...results)
          )
    : []

我将安装一个示例程序包，然后测试我们的功能-

$ npm install ramda
$ node

让我们看看它的工作原理-

> dirs (".") .then (console.log, console.error)

[ '.'
, 'node_modules'
, 'node_modules/ramda'
, 'node_modules/ramda/dist'
, 'node_modules/ramda/es'
, 'node_modules/ramda/es/internal'
, 'node_modules/ramda/src'
, 'node_modules/ramda/src/internal'
]

使用通用模块Parallel，我们可以简化dirs的定义-

const Parallel =
  require ("./Parallel")

const dirs = async (path = ".") =>
  (await stat (path)) .isDirectory ()
    ? Parallel (readdir (path))
        .flatMap (f => dirs (join (path, f)))
        .then (results => [ path, ...results ])
    : []

上面使用的Parallel模块是从一组旨在解决类似问题的函数中提取的模式。有关更多说明，请参见此related Q&A。

Answer 13

如果您需要使用所有async版本。你可以有这样的东西。

记录目录长度，将其用作指示器，以判断是否所有异步统计任务都已完成。
如果异步统计任务完成，则已检查所有文件统计信息，因此请调用回调

只有Node.js是单线程才会有效，因为它假定没有两个异步任务会同时增加计数器。

'use strict';

var fs = require("fs");
var path = require("path");
var basePath = "./";

function result_callback(results) {
    results.forEach((obj) => {
        console.log("isFile: " + obj.fileName);
        console.log("fileName: " + obj.isFile);
    });
};

fs.readdir(basePath, (err, files) => {
    var results = [];
    var total = files.length;
    var finished = 0;

    files.forEach((fileName) => {
        // console.log(fileName);
        var fullPath = path.join(basePath, fileName);

        fs.stat(fullPath, (err, stat) => {
            // this will work because Node.js is single thread
            // therefore, the counter will not increment at the same time by two callback
            finished++;

            if (stat.isFile()) {
                results.push({
                    fileName: fileName,
                    isFile: stat.isFile()
                });
            }

            if (finished == total) {
                result_callback(results);
            }
        });
    });
});

正如你所看到的，这是一种“深度优先”的方法，这可能导致回调地狱，并且它不是很“功能性”。人们试图通过将异步任务包装到Promise对象中来解决Promise这个问题。

'use strict';

var fs = require("fs");
var path = require("path");
var basePath = "./";

function result_callback(results) {
    results.forEach((obj) => {
        console.log("isFile: " + obj.fileName);
        console.log("fileName: " + obj.isFile);
    });
};

fs.readdir(basePath, (err, files) => {
    var results = [];
    var total = files.length;
    var finished = 0;

    var promises = files.map((fileName) => {
        // console.log(fileName);
        var fullPath = path.join(basePath, fileName);

        return new Promise((resolve, reject) => {
            // try to replace fullPath wil "aaa", it will reject
            fs.stat(fullPath, (err, stat) => {
                if (err) {
                    reject(err);
                    return;
                }

                var obj = {
                    fileName: fileName,
                    isFile: stat.isFile()
                };

                resolve(obj);
            });
        });
    });

    Promise.all(promises).then((values) => {
        console.log("All the promise resolved");
        console.log(values);
        console.log("Filter out folder: ");
        values
            .filter((obj) => obj.isFile)
            .forEach((obj) => {
                console.log(obj.fileName);
            });
    }, (reason) => {
        console.log("Not all the promise resolved");
        console.log(reason);
    });
});

Answer 14

CoffeeScript版this answer，具有正确的错误处理功能：

fs = require "fs"
{join} = require "path"
async = require "async"

get_subdirs = (root, callback)->
    fs.readdir root, (err, files)->
        return callback err if err
        subdirs = []
        async.each files,
            (file, callback)->
                fs.stat join(root, file), (err, stats)->
                    return callback err if err
                    subdirs.push file if stats.isDirectory()
                    callback null
            (err)->
                return callback err if err
                callback null, subdirs

取决于async

或者，use a module for this! （有一切模块。[需要引证]）

Answer 15

另一种递归方法

感谢Mayur认识我withFileTypes。我编写了以下代码来递归获取特定文件夹的文件。可以轻松地修改它以仅获取目录。

const getFiles = (dir, base = '') => readdirSync(dir, {withFileTypes: true}).reduce((files, file) => {
    const filePath = path.join(dir, file.name)
    const relativePath = path.join(base, file.name)
    if(file.isDirectory()) {
        return files.concat(getFiles(filePath, relativePath))
    } else if(file.isFile()) {
        file.__fullPath = filePath
        file.__relateivePath = relativePath
        return files.concat(file)
    }
}, [])

Answer 16

函数式编程

const fs = require('fs')
const path = require('path')
const R = require('ramda')

const getDirectories = pathName => {
    const isDirectory = pathName => fs.lstatSync(pathName).isDirectory()
    const mapDirectories = pathName => R.map(name => path.join(pathName, name), fs.readdirSync(pathName))
    const filterDirectories = listPaths => R.filter(isDirectory, listPaths)

    return {
        paths:R.pipe(mapDirectories)(pathName),
        pathsFiltered: R.pipe(mapDirectories, filterDirectories)(pathName)
    }
}

Answer 17

万一其他人从网络搜索结束到此处，并且Grunt已经在他们的依赖列表中，对此的答案变得微不足道。这是我的解决方案：

/**
 * Return all the subfolders of this path
 * @param {String} parentFolderPath - valid folder path
 * @param {String} glob ['/*'] - optional glob so you can do recursive if you want
 * @returns {String[]} subfolder paths
 */
getSubfolders = (parentFolderPath, glob = '/*') => {
    return grunt.file.expand({filter: 'isDirectory'}, parentFolderPath + glob);
}

Answer 18

带有ES6的完全异步版本，只有本地软件包fs.promises和async / await并行执行文件操作：

const fs = require('fs');
const path = require('path');

async function listDirectories(rootPath) {
    const fileNames = await fs.promises.readdir(rootPath);
    const filePaths = fileNames.map(fileName => path.join(rootPath, fileName));
    const filePathsAndIsDirectoryFlagsPromises = filePaths.map(async filePath => ({path: filePath, isDirectory: (await fs.promises.stat(filePath)).isDirectory()}))
    const filePathsAndIsDirectoryFlags = await Promise.all(filePathsAndIsDirectoryFlagsPromises);
    return filePathsAndIsDirectoryFlags.filter(filePathAndIsDirectoryFlag => filePathAndIsDirectoryFlag.isDirectory)
        .map(filePathAndIsDirectoryFlag => filePathAndIsDirectoryFlag.path);
}

经过测试，效果很好。

Answer 19

您可以使用以下模块来帮助自己：

npm dree

它有很多选择。您可以使用以下代码：

const dree = require('dree');

const options = {
  depth: 1
};
const fileCallback = function() {};

const directories = [];
const dirCallback = function(dir) {
 directories.push(dir.name);
};

dree.scan('./dir', {});

console.log(directories);

将打印指定路径（“ ./dir”）的直接子目录。

如果不放置选项depth: 1，甚至可以递归方式获取所有目录，不仅是指定路径的有向子级。

Answer 20

?graph-fs

安装

npm i graph-fs

使用

const {Node} = require("graph-fs");
const directory = new Node("/path/to/directory");

const names = directory.children  // <--
    .filter(node => node.is.directory)
    .map(directory => directory.name);

Answer 21

异步/等待变体：

async function getFolders(path) {
    let result = Array();
    let files = await fs.readdir(path);
    for (let i = 0; i < files.length; i++) {
        var filePath = path + '/' + file;
        if (await fs.stat(filePath).isDirectory()) {
            result.push(filePath);
        }
    }

    return result;
}

我还建议使用fs-extra代替fs。

获取目录nodejs中的所有目录

21 个答案:

递归解决方案

另一种递归方法

?graph-fs