Question

我对Python很陌生，所以这可能是一个愚蠢的问题，但无论如何我都会问。是否存在Django为这种常见的视图情况形成“设计模式”？当我运行视图时，我希望它根据填写表单的用户类型，对两种不同类型的表单中的一种进行操作。在if request.method块中有两个if / then块来确定我正在使用哪种类型的表单似乎很难看。我想要的是能够引用一个“CreateProfileForm”，它将引用CreateManProfileForm或CreateWomanProfileForm，具体取决于会话变量中的内容。

谢谢！

def create_profile(request, template):

    if request.session['user_type_cd'] == 'man':
        is_man = True
    else:
        is_man = False

    if request.method == "POST":
        if is_man:
            form = CreateManProfileForm(request.POST)
        else:
            form = CreateWomanProfileForm(request.POST)
        if form.is_valid():
            # Do stuff
            return HttpResponseRedirect(reverse('do-next-thing'))
    else:
        if is_man:
            form = CreateManProfileForm()
        else:
            form = CreateWomanProfileForm()

    return render_to_response(template, locals(), context_instance=RequestContext(request))

Answer 1

您可以这样做：

创建表单字典

FORMS = {
    0: CreateWomanProfileForm,
    1: CreateManProfileForm
}

在观点中：

def create_profile(request, template):
    is_man = 1 if request.session.get('user_type_cd') == 'man' else 0

    if request.method == "POST":
        form = FORMS.get(is_man)(request.POST)
        if form.is_valid():
            # Do stuff
            return HttpResponseRedirect(reverse('do-next-thing'))
    else:
        form = FORMS.get(is_man)()

    return render_to_response(template, locals(), context_instance=RequestContext(request))

甚至这应该可行

def create_profile(request, template):
    is_man = 1 if request.session['user_type_cd'] == 'man' else 0

    form = FORMS.get(is_man)(request.POST or None)
    if request.method == "POST":
        if form.is_valid():
            # Do stuff
            return HttpResponseRedirect(reverse('do-next-thing'))

    return render_to_response(template, locals(), context_instance=RequestContext(request))

Django为这种情况形成“模式”？

1 个答案: