我正在尝试用c ++编写2-3-4树的实现。我已经有一段时间了,因为我使用过模板,而且我遇到了一些错误。这是我非常基本的代码框架:
node.h:
#ifndef TTFNODE_H
#define TTFNODE_H
template <class T>
class TreeNode
{
private:
TreeNode();
TreeNode(T item);
T data[3];
TreeNode<T>* child[4];
friend class TwoThreeFourTree<T>;
int nodeType;
};
#endif
node.cpp:
#include "node.h"
using namespace std;
template <class T>
//default constructor
TreeNode<T>::TreeNode(){
}
template <class T>
//paramerter receving constructor
TreeNode<T>::TreeNode(T item){
data[0] = item;
nodeType = 2;
}
TwoThreeFourTree.h
#include "node.h"
#ifndef TWO_H
#define TWO_H
enum result {same, leaf,lchild,lmchild,rmchild, rchild};
template <class T> class TwoThreeFourTree
{
public:
TwoThreeFourTree();
private:
TreeNode<T> * root;
};
#endif
TwoThreeFourTree.cpp:
#include "TwoThreeFourTree.h"
#include <iostream>
#include <string>
using namespace std;
template <class T>
TwoThreeFourTree<T>::TwoThreeFourTree(){
root = NULL;
}
和main.cpp:
#include "TwoThreeFourTree.h"
#include <string>
#include <iostream>
#include <fstream>
using namespace std;
int main(){
ifstream inFile;
string filename = "numbers.txt";
inFile.open (filename.c_str());
int curInt = 0;
TwoThreeFourTree <TreeNode> Tree;
while(!inFile.eof()){
inFile >> curInt;
cout << curInt << " " << endl;
}
inFile.close();
}
当我尝试从命令行编译时: g ++ main.cpp node.cpp TwoThreeFourTree.cpp
我收到以下错误:
In file included from TwoThreeFourTree.h:1,
from main.cpp:1:
node.h:12: error: ‘TwoThreeFourTree’ is not a template
main.cpp: In function ‘int main()’:
main.cpp:13: error: type/value mismatch at argument 1 in template parameter list for ‘template<class T> class TwoThreeFourTree’
main.cpp:13: error: expected a type, got ‘TreeNode’
main.cpp:13: error: invalid type in declaration before ‘;’ token
In file included from node.cpp:1:
node.h:12: error: ‘TwoThreeFourTree’ is not a template
In file included from TwoThreeFourTree.h:1,
from TwoThreeFourTree.cpp:1:
node.h:12: error: ‘TwoThreeFourTree’ is not a template
我的主要问题是它为什么说“错误:'TwoThreeFourTree'不是模板”。有没有人有任何想法?感谢所有建议/帮助提前... 丹
答案 0 :(得分:8)
已接受的解决方案存在轻微的问题,即将您的类打开到TwoThreeFourTree
模板的任何实例化,而不仅仅是那些共享相同实例化类型的模板。
如果您只想打开类到相同类型的实例化,可以使用以下语法:
template <typename T> class TwoThreeFourTree; // forward declare the other template
template <typename T>
class TreeNode {
friend class TwoThreeFourTree<T>;
// ...
};
template <typename T>
class TwoThreeFourTree {
// ...
};
答案 1 :(得分:5)
使用friend关键字时,只需将其声明为模板即可。您在代码中使用了不正确的语法来表示朋友声明。你想写的是:
template <class U> friend class TwoThreeFourTree;