我可以将条件放入count()吗?让我解释一下。
START me=node:node_auto_index(UserProfileID = '1'), other=node(*)
MATCH pMutualFriends=me-[r?:friends]-mf-[r1:friends]-other
WHERE other.UserName? =~ '(?i)dh.*' AND other.UserProfileID? <> 1
RETURN me.EMailID, other.EMailID,other.UserProfileID, other.UserName, r.ApprovalStatus, COUNT(pMutualFriends) AS mutualCount
在上面的查询中我可以像这样使用。
COUNT(pMutualFriends where r.ApprovalStatus = 1 AND r1.ApprovalStatus =1 )
或者可能以其他方式?
由于
答案 0 :(得分:1)
filter
function应该对你有所帮助。如果您需要进一步的帮助,请在http://console.neo4j.org上提供数据样本并在此处分享。
举个例子:
START me=node:node_auto_index(UserProfileID = '1'), other=node(*)
MATCH pMutualFriends=me-[r?:friends]-mf-[r1:friends]-other
WHERE other.UserName? =~ '(?i)dh.*' AND other.UserProfileID? <> 1
RETURN me.EMailID, other.EMailID,other.UserProfileID, other.UserName,
count(filter(x IN r.ApprovalStatus: x=1)),
count(filter(x IN r1.ApprovalStatus: x=1))