我只收到一个通知,如果有另一个通知,它会替换上一个通知,这是我的代码
private static void generateNotification(Context context, String message,
String key) {
int icon = R.drawable.ic_launcher;
long when = System.currentTimeMillis();
NotificationManager notificationManager = (NotificationManager) context
.getSystemService(Context.NOTIFICATION_SERVICE);
Notification notification = new Notification(icon, message, when);
String title = context.getString(R.string.app_name);
Intent notificationIntent = new Intent(context,
FragmentOpenActivity.class);
notificationIntent.putExtra(key, key);
// set intent so it does not start a new activity
notificationIntent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP
| Intent.FLAG_ACTIVITY_SINGLE_TOP);
PendingIntent intent = PendingIntent.getActivity(context, 0,
notificationIntent, 0);
notification.setLatestEventInfo(context, title, message, intent);
notification.flags |= Notification.FLAG_AUTO_CANCEL;
notification.defaults |= Notification.DEFAULT_SOUND;
// notification.sound = Uri.parse("android.resource://" +
// context.getPackageName() + "your_sound_file_name.mp3");
notification.defaults |= Notification.DEFAULT_VIBRATE;
notificationManager.notify(0, notification);
}
答案 0 :(得分:114)
只需用这个
替换你的行 notificationManager.notify(Unique_Integer_Number, notification);
希望它会对你有所帮助。
答案 1 :(得分:70)
简单的notification_id需要改变。
只需为notification_id创建随机数。
Random random = new Random();
int m = random.nextInt(9999 - 1000) + 1000;
或者您可以使用此方法创建tieorange告知的随机数(这永远不会重复):
int m = (int) ((new Date().getTime() / 1000L) % Integer.MAX_VALUE);
并替换此行以添加通知ID的参数以生成随机数
notificationManager.notify(m, notification);
答案 2 :(得分:27)
使用共享首选项为我工作
SharedPreferences prefs = getSharedPreferences(Activity.class.getSimpleName(), Context.MODE_PRIVATE);
int notificationNumber = prefs.getInt("notificationNumber", 0);
...
notificationManager.notify(notificationNumber , notification);
SharedPreferences.Editor editor = prefs.edit();
notificationNumber++;
editor.putInt("notificationNumber", notificationNumber);
editor.commit();
答案 3 :(得分:8)
用此替换你的行。
notificationManager.notify((int) ((new Date().getTime() / 1000L) % Integer.MAX_VALUE), notification);
答案 4 :(得分:8)
我想这会帮助别人..
在下面的代码" not_nu"是一个随机的int .. PendingIntent和Notification具有相同的ID ..所以在每个通知上点击意图将指向不同的活动..
private void sendNotification(String message,String title,JSONObject extras) throws JSONException {
String id = extras.getString("actionParam");
Log.e("gcm","id = "+id);
Intent intent = new Intent(this, OrderDetailActivty.class);
intent.putExtra("id", id);
intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
final int not_nu=generateRandom();
PendingIntent pendingIntent = PendingIntent.getActivity(this, not_nu /* Request code */, intent,
PendingIntent.FLAG_ONE_SHOT);
Uri defaultSoundUri= RingtoneManager.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION);
NotificationCompat.Builder notificationBuilder = new NotificationCompat.Builder(this)
.setSmallIcon(R.mipmap.ic_cart_red)
.setContentTitle(title)
.setContentText(message)
.setAutoCancel(true)
.setSound(defaultSoundUri)
.setContentIntent(pendingIntent);
NotificationManager notificationManager =
(NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);
notificationManager.notify(not_nu /* ID of notification */, notificationBuilder.build());
}
public int generateRandom(){
Random random = new Random();
return random.nextInt(9999 - 1000) + 1000;
}
答案 5 :(得分:5)
在uniqueIntNo
的地方放置如下的唯一整数:
mNotificationManager.notify(uniqueIntNo, builder.build());
答案 6 :(得分:3)
您需要为每个通知添加唯一ID,以便它们不会相互组合。您可以使用此链接作为参考:
https://github.com/sanathe06/AndroidGuide/tree/master/ExampleCompatNotificationBuilder
答案 7 :(得分:3)
另一种方法是将当前日期转换为long,只取最后4位数。该数字很可能是唯一的。
long time = new Date().getTime();
String tmpStr = String.valueOf(time);
String last4Str = tmpStr.substring(tmpStr.length() -5);
int notificationId = Integer.valueOf(last4Str);
答案 8 :(得分:3)
我解决了这个问题......
/**
* Issues a notification to inform the user that server has sent a message.
*/
private static void generateNotification(Context context, String message,
String keys, String msgId, String branchId) {
int icon = R.drawable.ic_launcher;
long when = System.currentTimeMillis();
NotificationCompat.Builder nBuilder;
Uri alarmSound = RingtoneManager
.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION);
nBuilder = new NotificationCompat.Builder(context)
.setSmallIcon(R.drawable.ic_launcher)
.setContentTitle("Smart Share - " + keys)
.setLights(Color.BLUE, 500, 500).setContentText(message)
.setAutoCancel(true).setTicker("Notification from smartshare")
.setVibrate(new long[] { 100, 250, 100, 250, 100, 250 })
.setSound(alarmSound);
String consumerid = null;
Integer position = null;
Intent resultIntent = null;
if (consumerid != null) {
if (msgId != null && !msgId.equalsIgnoreCase("")) {
if (key != null && key.equalsIgnoreCase("Yo! Matter")) {
ViewYoDataBase db_yo = new ViewYoDataBase(context);
position = db_yo.getPosition(msgId);
if (position != null) {
resultIntent = new Intent(context,
YoDetailActivity.class);
resultIntent.putExtra("id", Integer.parseInt(msgId));
resultIntent.putExtra("position", position);
resultIntent.putExtra("notRefresh", "notRefresh");
} else {
resultIntent = new Intent(context,
FragmentChangeActivity.class);
resultIntent.putExtra(key, key);
}
} else if (key != null && key.equalsIgnoreCase("Message")) {
resultIntent = new Intent(context,
FragmentChangeActivity.class);
resultIntent.putExtra(key, key);
}.
.
.
.
.
.
} else {
resultIntent = new Intent(context, FragmentChangeActivity.class);
resultIntent.putExtra(key, key);
}
} else {
resultIntent = new Intent(context, MainLoginSignUpActivity.class);
}
PendingIntent resultPendingIntent = PendingIntent.getActivity(context,
notify_no, resultIntent, PendingIntent.FLAG_UPDATE_CURRENT);
if (notify_no < 9) {
notify_no = notify_no + 1;
} else {
notify_no = 0;
}
nBuilder.setContentIntent(resultPendingIntent);
NotificationManager nNotifyMgr = (NotificationManager) context
.getSystemService(context.NOTIFICATION_SERVICE);
nNotifyMgr.notify(notify_no + 2, nBuilder.build());
}
答案 9 :(得分:0)
以下是传递唯一通知ID的代码:
//"CommonUtilities.getValudeFromOreference" is the method created by me to get value from savedPreferences.
String notificationId = CommonUtilities.getValueFromPreference(context, Global.NOTIFICATION_ID, "0");
int notificationIdinInt = Integer.parseInt(notificationId);
notificationManager.notify(notificationIdinInt, notification);
// will increment notification id for uniqueness
notificationIdinInt = notificationIdinInt + 1;
CommonUtilities.saveValueToPreference(context, Global.NOTIFICATION_ID, notificationIdinInt + "");
//Above "CommonUtilities.saveValueToPreference" is the method created by me to save new value in savePreferences.
重置特定范围的savedPreferences中的notificationId,就像我在1000处所做的那样。因此将来不会产生任何问题。 如果您需要更多详细信息或任何查询,请与我们联系。 :)
答案 10 :(得分:0)
问题在于您的notificationId
。将其视为数组索引。每次更新通知时,notificationId
都是存储值所需的位置。由于您没有递增int值(在本例中为notificationId
),因此总是替换前一个值。我想最好的解决方案是在更新通知后立即增加它。如果您想保持持久性,那么您可以将notificationId
的值存储在sharedPreferences
中。每当你回来时,你只需抓住最后一个整数值(notificationId
中存储的sharedPreferences
)并使用它。
答案 11 :(得分:0)
在代码中使用以下方法。
方法调用: -
notificationManager.notify(getCurrentNotificationId(getApplicationContext()), notification);
方法: -
*Returns a unique notification id.
*/
public static int getCurrentNotificationId(Context iContext){
NOTIFICATION_ID_UPPER_LIMIT = 30000; // Arbitrary number.
NOTIFICATION_ID_LOWER_LIMIT = 0;
SharedPreferences sharedPreferences = PreferenceManager.getDefaultSharedPreferences(iContext);
int previousTokenId = sharedPreferences.getInt("currentNotificationTokenId", 0);
int currentTokenId = previousTokenId+1;
SharedPreferences.Editor editor = sharedPreferences.edit();
if(currentTokenId<NOTIFICATION_ID_UPPER_LIMIT) {
editor.putInt("currentNotificationTokenId", currentTokenId); // }
}else{
//If reaches the limit reset to lower limit..
editor.putInt("currentNotificationTokenId", NOTIFICATION_ID_LOWER_LIMIT);
}
editor.commit();
return currentTokenId;
}
答案 12 :(得分:0)
notificationManager.notify(0, notification);
putthis new Random().nextInt() in position of 0
like below it works for me
notificationManager.notify(new Random().nextInt(), notification);
答案 13 :(得分:0)
您只需要将单行从DataGridTextColumn
更改为private static bool CanEditCell(DataGridCell cell)
{
if (!(cell.Column is DataGridTemplateColumn col)) return false; //TemplateColumns only
//dont process noneditable or already editing cell
return !(cell.IsEditing || cell.IsReadOnly);
}
private static void DataGrid_PreviewTextInput(object sender, TextCompositionEventArgs e)
{
//ignore non-key input related events, e.g. ctrl+c/ctrl+v
if (string.IsNullOrEmpty(e.Text)) return;
if (e.Source is DataGrid dg &&
e.OriginalSource is DataGridCell cell &&
CanEditCell(cell))
{
dg.BeginEdit();
//custom extension method, see
var tb = cell.GetVisualChild<TextBox>();
tb?.Focus(); //route current event into the input control
tb?.SelectAll(); //overwrite contents
}
}
...
这将在新的通知出现时更改通知的ID
答案 14 :(得分:0)
对于Kotlin。
notificationManager.notify(Calendar.getInstance().timeInMillis.toInt(),notificationBuilder.build())
答案 15 :(得分:-1)
一个简单的计数器可以解决您的问题。
private Integer notificationId = 0;
private Integer incrementNotificationId() {
return notificationId++;
}
NotificationManager.notify(incrementNotificationId, notification);
答案 16 :(得分:-1)
declare class member
static int i = 0;
mNotificationManager.notify(++i, mBuilder.build());
答案 17 :(得分:-1)
val notifyIdLong = ((Date().time / 1000L) % Integer.MAX_VALUE)
var notifyIdInteger = notifyIdLong.toInt()
if (notifyIdInteger < 0) notifyIdInteger = -1 * notifyIdInteger // if it's -ve change to positive
notificationManager.notify(notifyIdInteger, mBuilder.build())
log.d(TAG,"notifyId = $notifyIdInteger")